Answer:
C2, C1, C4, C5 and C6 are in parallel. Therefore, we use the formula Cp = C1 + C2 + ....
Cp = C2 + C1 + C4 + C5 + C6 = ( 7 * 10 ^-3) + (18 * 10^-6) + (0.8F) + (200 * 10^-3 F) + (750 * 10^-6) = 1.008F
Now, Cp will become one capacitor and it will be aligned with C3, therefore it will now become a circuit in series.
We use the formula: 1/Cs = 1/C1 + 1/C2 + .... + ....1/Cn
Thus,
1/Cs = 1/C3 + 1/Cp
1/Cs = 1/(14 * 10^-3 F) + 1/(1.008F)
Cs = 1.4 * 10 ^-2 or if we do not round too much it will give exactly 0.0138 F
So the answer should be a)
Answer:
As the wavelength of an electromagnetic wave _decrease__ the frequency of the wave _increase_______.
Explanation:
What is the relationship between frequency and wavelength?
Wavelength and frequency of light are closely related. The higher the frequency, the shorter the wavelength. Because all light waves move through a vacuum at the same speed, the number of wave crests passing by a given point in one second depends on the wavelength.
That number, also known as the frequency, will be larger for a short-wavelength wave than for a long-wavelength wave. The equation that relates wavelength and frequency is:
V= fλ
where v= velocity
f= frequency
λ = wavelength
⇒ f = v/λ
also f ∝ 1/λ
For electromagnetic radiation, the speed is equal to the speed of light, c, and the equation becomes:
C= fλ
where c= Speed of light
f= frequency
λ = wavelength
⇒ f = v/λ
also f ∝ 1/λ
The magnitude of the force exerted by the left cube on the right cube is 17.64N.
<h3>What is frictional force?</h3>
When an object is moving on a rough surface, it experiences opposition. This opposing force is called the friction.
Two identical 3.0-kg cubes are placed on a horizontal surface in contact with one another. The cubes are lined up from left to right and a force F₁ is applied to the left side of the left cube causing both cubes to move at a constant speed v. The coefficient of kinetic friction between the cubes and the surface is 0.3.
From the equilibrium of forces in vertical direction
Normal force N= 2m x g
friction force f = μN =μ(2m)g
From the equilibrium of forces in horizontal direction
F₁ =ma =0
using Newton's third law of motion, we get
F₁ - f =0
F₁ =f = μ(2m)g
Put the values, we get
F₁ = 17.64N
Thus, magnitude of the force exerted by the left cube on the right cube is 17.64N.
Learn more about friction force.
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Any one trial might have been done incorrectly.
Answer:
C
Explanation:
The period of a pendulum is found by the equation: T = 2pi*sqrt(L/g). Let the original length be L and the original period be T. The length increased by a factor of 4, so it’s new length is 4L. We get that the new period is 2pi*sqrt(4L/g) = 2pi*2sqrt(L/g) = 4pi*sqrt(L/g). We can see that the period increased by a factor of 2 because the original period, T, equals 2pi*sqrt(L/g) and the new period is 4pi*sqrt(L/g) = 2(2pi*sqrt(L/g)) = 2T. Therefore, the new period is 2(1.4) = 2.8
I hope this helps! :)
