Answer:
Is this your ans of this question
Answer:
m₁ (R +ℓ/2) / /( m₁ + m₂ )
Explanation:
We shall consider centre of the club's head as origin .
The centre of mass of the rod attached with sphere will be away from the centre of sphere by a distance
= R + ℓ /2 and its mass is m₁
mass of sphere is m₂ and distance of its centre of mass from origin is zero
So required CM = m₁ x₁ + m₂ x₂ / ( m₁ + m₂ )
= m₁ (R + ℓ /2) + m₂ x 0 /( m₁ + m₂ )
= m₁ (R +ℓ/2) / /( m₁ + m₂ )
Hi , I think that the elements that have one valence electron and that are in the alkali metals are the answers .
1.lithium
2.sodium
3.potassium
4.rubidium
5.cesium
6.francium
Answer:
0.08
Explanation:
this problem assume that both of whale and submarine are in rest position or in constant linier motion in same direction and same speed.
The sound will travel from Submarine to the whale and back again to submarine. so the time will be like this
t = 2d/v
t = 2*58.8/1520
t = 117.6/1520
t = 0.077368 s
t ≈ 0.08 s (less then 1 s)
Answer:
When the string moves, it creates a very small change in the distance to the next point, th
Explanation:
When the string moves, it creates a very small change in the distance to the next point, this generates a restoring force that tends to push the string back, this small disturbance propagates along the string and is what creates the pulse.
This is similar to what happens when a spring is stretched and a restoring force is generated shaved by the law of shortening.
F = k Dx
