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Basile [38]
3 years ago
5

TRUE OR FALSE. if an object covers equal distance at equal intervals of time, then it is moving at constant speed and not accele

rating
Physics
1 answer:
Novay_Z [31]3 years ago
8 0

Answer:

True

Explanation:

Speed = distance/time

If distance and time are the same, then the right hand side of the equation remains the same, causing us to solve the left to the same value

As the distance is the same (say 50m) and the time is the same (say 50s) then the speed must be the same (1m/s)

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A 13 kg hanging sculpture is suspended by a 95-cm-long, 5.0 g steel wire. When the wind blows hard, the wire hums at its fundame
Artyom0805 [142]

Answer:

f=81.96 \ Hz

Explanation:

Givens

L=95cm

m_{sculpture} =13kg

m_{wire}=5g

The frequency is defined by

f=\frac{v}{\lambda}

Where v is the speed of the wave in the string and \lambda is its wave length.

The wave length is defined as \lambda = 2L = 2(0.95m)=1.9m

Now, to find the speed, we need the tension of the wire and its linear mass density

v=\sqrt{\frac{T}{\mu} }

Where \mu=\frac{0.005kg}{0.95m}= 5.26 \times 10^{-3} and the tension is defined as T=m_{sculpture} g=13kg(9.81 m/s^{2} )=127.53N

Replacing this value, the speed is

v=\sqrt{\frac{127.53N}{5.26 \times 10^{-3} } }=155.71 m/s

Then, we replace the speed and the wave length in the first equation

f=\frac{v}{\lambda}\\f=\frac{155.71 m/s}{1.9m}\\ f=81.96Hz

Therefore, the frequency is f=81.96 \ Hz

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2 years ago
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What were the patterns that people saw in the sky long ago?
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Long time ago, people saw the constellations as patterns in the sky.  They names these patterns and tell stories about them. What people saw laong time ago are just mere patterns which forms animals and shapes.  We got the names of our constellations from the Greeks who named the constellations after the mythological heroes and mythological legends.
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3 years ago
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Suppose two carts, one twice as massive as the other, fly apart when the
disa [49]

Answer:

the question this morning

Explanation:

90+70 look than

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2 years ago
6. A pitcher throws a ball toward home plate 18.39 meters away. If the ball is traveling at a constant 40.0 m/s, how long does i
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3 0
3 years ago
Suppose that two point charges, each with a charge of +3.00 Coulomb are separated by a distance of 3.00 meters. Determine the ma
Sveta_85 [38]

Answer:

9\cdot 10^9 N

Explanation:

The magnitude of the electrical force between the two point charges is

F=k\frac{q_1 q_2}{r^2}

where

k is the Coulomb's constant

q_1 =q_2 = +3.0 C is the magnitude of each charge

r = 3.00 m is the separation between the two charges

Substituting the numbers into the formula, we find

F=(9\cdot 10^9 Nm^2C^{-2})\frac{(+3 C)^2}{(3.00 m)^2}=9\cdot 10^9 N

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