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Basile [38]
3 years ago
5

TRUE OR FALSE. if an object covers equal distance at equal intervals of time, then it is moving at constant speed and not accele

rating
Physics
1 answer:
Novay_Z [31]3 years ago
8 0

Answer:

True

Explanation:

Speed = distance/time

If distance and time are the same, then the right hand side of the equation remains the same, causing us to solve the left to the same value

As the distance is the same (say 50m) and the time is the same (say 50s) then the speed must be the same (1m/s)

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Please help me!
sergeinik [125]

C. The Densities are equal.

<h3>What is density?</h3>

Density is mass per unit volume or mass of a unit volume of a material substance.

If m1, V1 and D1 = mass, volume  and density respectively of ball C

m2, V2 and D2 = mass, volume and density respectively of ball D

According to the Question ,

V_{1} = 3V_{2}  , m_{2}  = \frac{1}{3} (m_{1} ) \\ \\= m_{1} = 3m_{2}

Therefore,

\frac{D_{1} }{D_{2} }  = (\frac{m_{1} }{V_{1} } )* (\frac{m_{2} }{V_{2} } )\\ \\= (\frac{3m_{2} }{3V_{2} })*(\frac{V_{2} }{m_{2} }) \\\\= 1

Hence, D1 = D2

Learn more about density here:brainly.com/question/15164682

#SPJ1

6 0
2 years ago
What is the acceleration of a 5kg rock that is thrown with a force of 18N?
natita [175]

Answer:

F = m×a

a = F /m

a = 90 m/s²

hope it's helps you

8 0
3 years ago
A spherical steel ball bearing has a diameter of 2.540 cm at 20.00°C. (Assume the coefficient of linear expansion for steel is 1
shusha [124]

Answer:

(a) 2.542 cm

(b) 272.7°C

Explanation:

diameter, d = 2.540 cm

T1 = 20°C

α = 11 x 10^-6 /°C

(a) Let d' be the diameter.

T2 = 87°C

Use he formula for the areal expansion

A' = A ( 1 + βΔT)

where, β is the coefficient of areal expansion and ΔT is teh rise in temperature, A' be the area at high temperature and A be the area at low temperature.

β = 2 α = 2 x 11 x 106-6 = 22 x 10^-6 /°C

So,

\frac{\pi D'^{2}}{4}=\frac{\pi D^{2}}{4}\left ( 1+\beta \Delta T \right )

D'^2 = 2.54^2 ( 1 + 22 x 10^-6 x 67)

D' = 2.542 cm

(b) Let the change in temperature is ΔT.

Use the formula for the volumetric expansion

ΔV = V x γ x ΔT

Where, γ = 3 x α = 3 x 11 x 10^-6 = 33 x 10^-6 /°C

0.9/100 = 33 x 10^-6 x ΔT

ΔT = 272.7°C

6 0
3 years ago
PLEASE HELP ASAP!!
maria [59]

Velocity is displacement over time, so do 60/8 to get 7.5 yards per second, and remember to add the direction the ball is traveling in.

3 0
3 years ago
An average person can reach a maximum height of about 60 cm when jumping straight up from a crouched position. during the jump i
mariarad [96]
1) You can find the velocity with which the jumper leaves the ground by using the formula for the final velocity of an upward vertical motion.

Vf^2 = Vo^2 - 2gd

The data known are: Vf = 0, g = 9.81 m/s^2,   and d = 60 cm = 0.6 m

=> Vo^2 = 2gd = 2*9.81m/s^2 * 0.6 m = .11.772 m^2/s^2 =>

Vo = 3.4 m/s

2) You can obtain the acceleration of the jumper during the jump by using the equivalent formula, Vf^2 = Vo^2 + 2ad

Where, Vf^2 is the velocity with which he leaves the ground (3.4 m/s), Vo is zero because he jumps from the rest, d is the distance that his body rises from knees,which is 50 cm = 0.5 m

Then,  a = Vf^2 / 2d = [3.4m/s]^2 / (2*0.5m) =   11.6 m/s^2

And now, you can find the force exerted by the jumper as:

F = m*a, and if you know his weight, W = m*g => m = W/g

Replace m in F = m*a => F = W*a/g = W*11.6m/s^2 / 9.81 m/s^2 = 0.10 W

F = 0.10 W 

 
6 0
3 years ago
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