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Deffense [45]
4 years ago
12

Construct a dichotmous key to differentiate among particles in a solid,liquid and a gas.​

Mathematics
2 answers:
sergey [27]4 years ago
8 0

Answer:

compressed , unfixed , spread'

Step-by-step explanation:

gregori [183]4 years ago
4 0

Answer:

i dont understand

Step-by-step explanation:

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One urn contains one blue ball (labeled B1) and three red balls (labeled R1, R2, and R3). A second urn contains two red balls (R
marusya05 [52]

Answer:

(a) See attachment for tree diagram

(b) 24 possible outcomes

Step-by-step explanation:

Given

Urn\ 1 = \{B_1, R_1, R_2, R_3\}

Urn\ 2 = \{R_4, R_5, B_2, B_3\}

Solving (a): A possibility tree

If urn 1 is selected, the following selection exists:

B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]

If urn 2 is selected, the following selection exists:

B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]

<em>See attachment for possibility tree</em>

Solving (b): The total number of outcome

<u>For urn 1</u>

There are 4 balls in urn 1

n = \{B_1,R_1,R_2,R_3\}

Each of the balls has 3 subsets. i.e.

B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]

So, the selection is:

Urn\ 1 = 4 * 3

Urn\ 1 = 12

<u>For urn 2</u>

There are 4 balls in urn 2

n = \{B_2,B_3,R_4,R_5\}

Each of the balls has 3 subsets. i.e.

B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]

So, the selection is:

Urn\ 2 = 4 * 3

Urn\ 2 = 12

Total number of outcomes is:

Total = Urn\ 1 + Urn\ 2

Total = 12 + 12

Total = 24

5 0
3 years ago
PLS HELP TIMED QUESTION!!!
ser-zykov [4K]

Answer:

About 5043.58

Step-by-step explanation:

The standard form for an exponential decay after t time is:

\displaystyle f(t)=a(r)^{t/d}

Where a is the initial value, r is the rate decay, t is the time that has passed, and d is the amount of time it takes for 1 cycle.

The initial value is 9800. So a = 9800.

The quantity cuts in half. So, r = 1/2.

And it cuts in half every 6 days. For this question, we will convert this to hours. 6 days = 144 hours. So, we can let d = 144, where t will be in hours.

Therefore, our function is:

\displaystyle f(t)=9800\Big(\frac{1}{2}\Big)^{t/144}

Where t is the amount of time that has passed, in hours.

Then the quantity left after 138 hours will be:

\displaystyle f(138)=9800\Big(\frac{1}{2}\Big)^{138/144}\approx 5043.58

7 0
3 years ago
What is the slope and y intercept of the points (4,8) and (20,24)​
marissa [1.9K]
The slope is 1 and the y intercept is 0
8 0
3 years ago
Ashley recently opened a store that uses only natural ingredients. She wants to advertise her products by distributing bags of s
irakobra [83]

Answer:

5 1/3 hours.

Step-by-step explanation:

Ashley prepares 1 bag in 2/3 minutes.

One friend takes 2/3 + 3/4 * 2/3 = 7/6 minutes to make 1 bag.

4 of her friends can make 1 bag in 7/6 * 1/4 = 7/24 minutes.

If it takes x minutes for  Ashley and 4 friends to make one bag then we have:

1 / 2/3  + 1 / 7/24 = 1 / x

3/2 + 24/7 = 1/x

Multiply through by 14x:

21x + 48x = 14

x = 14/69 minutes.

So the  time to make 1575 bags = 1575 * 14/69

=  320 minutes.

5 0
3 years ago
Read 2 more answers
Which ordered pair is the solution to the system of inequalities
Kryger [21]

Answer:

C) (9, 4)

Step-by-step explanation:

4 < 5☑

4 < 3[9] → 4 < 27☑

Therefore, this solution is genuine.

I am joyous to assist you anytime.

3 0
3 years ago
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