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Deffense [45]
3 years ago
12

Construct a dichotmous key to differentiate among particles in a solid,liquid and a gas.​

Mathematics
2 answers:
sergey [27]3 years ago
8 0

Answer:

compressed , unfixed , spread'

Step-by-step explanation:

gregori [183]3 years ago
4 0

Answer:

i dont understand

Step-by-step explanation:

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2/3 (5 x 4) ÷ 3 + 6/7 I divided 3/2 is 1.5*(20)=30/3=10+1.16=11.16 is that correct not so good in math
Assoli18 [71]
\frac{2}{3}(5*4):3+ \frac{6}{7} = \\ \\  \frac{2}{3}*20:3+ \frac{6}{7} = \\ \\   \frac{40}{3}:3+ \frac{6}{7} = \\ \\\frac{40}{9}+ \frac{6}{7}= \\ \\  \frac{40*7+6*9}{7*9}= \\ \\\frac{280+54}{63}= \\ \\  \frac{334}{63} = \\ \\  5 \frac{19}{63} \ \ \  [as \ a \  mixed \ fraction] \\ \\ \approx 5.3 \ \ \  [as \ a \  decimal\ fraction \ to \ the \ nearest \ tenth]
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3 years ago
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What is the solution to 2 6/7 divided by 2/14
Black_prince [1.1K]
The answer is 10 i believe 
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3 years ago
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There were 29 students available for the woodwind section of the school orchestra. 11 students could play the flute, 15 could pl
Dafna11 [192]

Answer:

a. The number of students who can play all three instruments = 2 students

b. The number of students who can play only the saxophone is 0

c. The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only one of the clarinet, saxophone, or flute = 4

Step-by-step explanation:

The total number of students available = 29

The number of students that can play flute = 11 students

The number of students that can play clarinet = 15 students

The number of students that can play saxophone = 12 students

The number of students that can play flute and saxophone = 4 students

The number of students that can play flute and clarinet = 4 students

The number of students that can play clarinet and saxophone = 6 students

Let the number of students who could play flute = n(F) = 11

The number of students who could play clarinet = n(C) = 15

The number of students who could play saxophone = n(S) = 12

We have;

a. Total = n(F) + n(C) + n(S) - n(F∩C) - n(F∩S) - n(C∩S) + n(F∩C∩S) + n(non)

Therefore, we have;

29 = 11 + 15 + 12 - 4 - 4 - 6 + n(F∩C∩S) + 3

29 = 24 + n(F∩C∩S) + 3

n(F∩C∩S) = 29 - (24 + 3) = 2

The number of students who can play all = 2

b. The number of students who can play only the saxophone = n(S) - n(F∩S) - n(C∩S) - n(F∩C∩S)

The number of students who can play only the saxophone = 12 - 4 - 6 - 2 = 0

The number of students who can play only the saxophone = 0

c. The number of students who can play the saxophone and the clarinet but not the flute = n(C∩S) - n(F∩C∩S) = 6 - 2 = 4

The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only the saxophone = 0

The number of students who can play only the clarinet = n(C) - n(F∩C) - n(C∩S) - n(F∩C∩S) = 15 - 4 - 6 - 2 = 3

The number of students who can play only the clarinet = 3

The number of students who can play only the flute = n(F) - n(F∩C) - n(F∩S) - n(F∩C∩S) = 11 - 4 - 4 - 2 = 1

The number of students who can play only the flute = 1

Therefore, the number of students who can play only one of the clarinet, saxophone, or flute = 1 + 3 + 0 = 4

The number of students who can play only one of the clarinet, saxophone, or flute = 4.

6 0
3 years ago
Help Please Math!!!<br> Find The Surface Area Of The Prism
LiRa [457]

Answer:

Surface Area=208 cm²

Step-by-step explanation:

Surface Area= 2×l×w+2×l×h+2×h×w

SA= 2×11×4+2×4×4+2×11×4=208

8 0
2 years ago
Which one is this please answer it and get thanks from me if ur right
mote1985 [20]

♡ The Question ♡

- Which of the following is equivalent to the power shown below? 8^4

*୨୧ ┈┈┈┈┈┈┈┈┈┈┈┈ ୨୧*

☆ The Answer ☆

- Your answer should be C!

*୨୧ ┈┈┈┈┈┈┈┈┈┈┈┈ ୨୧*

♡ The Explanation/Step-By-Step ♡

- When your power is being shown as 8^4, this can be represented as 'Eight four times.' This means it could be, 8, 8, 8, 8. Hope this helps!

*୨୧ ┈┈┈┈┈┈┈┈┈┈┈┈ ୨୧*

☆ Tips ☆

- No tips provided!

4 0
2 years ago
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