Based on your solubility rules which of the following compounds would form a precipitate water?

In which sample are the particles arranged in a regular geometric pattern?

andrew11 [14]

There is no picture hunny. Please add a picture please boo.

7 0

3 years ago

1.- Ilumina de amarillo los verbos en pretérito y de verde los verbos en copretérito.

ivanzaharov [21]

Answer:

Pretérito (Pretérito perfecto):

estiró, sudó, peleó, compartí

Copretérito (Pretérito imperfecto):

saludaba, pedias, leia, compraba, barrias, cargaba, estrenabas, escribian

Explanation:

Los verbos en pretérito, también llamado pretérito perfecto, son los siguientes:

estiró, sudó, peleó, compartí

Como se aprecia, los verbos conjugados en pretérito perfecto terminan la última sílaba en vocal con acento, es decir, -á, -é, -í u -ó.

Los verbos en copretérito, también llamado pretérito imperfecto, son los siguientes:

saludaba, pedias, leia, compraba, barrias, cargaba, estrenabas, escribian

Como se aprecia, los verbos conjugados en pretérito imperfecto terminan la última sílaba en -ía, ías, -ían, -aba, -abas o -aban.

3 0

2 years ago

Based on the activity series of metal, which reaction with water will not happen?

laila [671]

Answer:

B

Explanation:

B, H2O + Na The elements toward the bottom left corner of the periodic table are the metals that are the most active in the sense of being the most reactive. Lithium, sodium, and potassium all react with water,

5 0

2 years ago

Pu is a nuclear waste byproduct with a half-life of 24,000 y. What fraction of the 239Pu present today will be present in 1000 y

olya-2409 [2.1K]

Answer:

0.9715 Fraction of Pu-239 will be remain after 1000 years.

Explanation:

$\lambda =\frac{0.693}{t_{\frac{1}{2}}}$

$A=A_o\times e^{-\lambda t}$

Where:

$\lambda$ = decay constant

$A_o$ =concentration left after time t

$t_{\frac{1}{2}}$ = Half life of the sample

Half life of Pu-239 = $t_{\frac{1}{2}}=24,000 y$ [

$\lambda =\frac{0.693}{24,000 y}=2.8875\times 10^{-5} y^{-1]$

Let us say amount present of Pu-239 today = $A_o=x$

A = ?

$A=x\times e^{-2.8875\times 10^{-5} y^{-1]\times 1000 y}$

$A=0.9715\times x$

$\frac{A}{A_0}=\frac{A}{x}=0.9715$

0.9715 Fraction of Pu-239 will be remain after 1000 years.

7 0

3 years ago

Which of the following is a possible set of quantum numbers for an electron (n,l,m0,ms) ?

Mashutka [201]

Answer is: (3, 2, 0, -1/2).

The principal quantum number (n) is one of four quantum numbers which are assigned to each electron in an atom to describe that electron's state.

For principal quantum number n=3:

1) azimuthal quantum number (l) can be l = 0...n-1:

l = 0, 1, 2.

The azimuthal quantum number determines its orbital angular momentum and describes the shape of the orbital.

2) magnetic quantum number (ml) can be ml = -l...+l.

ml = -2, -1, 0, +1, +2.

Magnetic quantum number specify orientation of electrons in magnetic field and number of electron states (orbitals) in subshells.

3) the spin quantum number (ms), is the spin of the electron.

ms = +1/2, -1/2.

(1, 1, 0, +1/2) is not correct because orbital quantum number cannot be l = 1 for n = 1.

(2, 1, 2, +1/2) is not correct because magnetic quantum number cannot be ml = 2 for orbital quantum number l = 1.

(3, -2, 1, -1/2) is not correct because orbital quantum number cannot be l = -2 for principal quantum number n = 3.

5 0

3 years ago