<span>equal and acting on different objects</span>
<h2>Sorry, But I don't know!!</h2>
Refer to the diagram shown below.
W₁ = (4 kg)*(9.8 m/s²) = 39.2 N
W₂ = (1 kg)*(9.8 m/s²) = 9.8 N
The normal reaction on the 4-kg mass is
N = (39.2 N)*cos(25°) = 35.5273 N
The force acting down the inclined plane due to the weight is
F = (39.2 N)*sin(25°) = 16.5666 N
The net force that accelerates the 4-kg mass at a m/²s down the plane is
F - W₂ = (4 kg)*(a m/s²)
4a = 16.5666 - 9.8
a = 1.6917 m/s²
Answer: 1.69 m/s² (nearest hundredth)
Answer:
a. slope=rise/run
rise=0.02
run=-2
determined using the point (3,0.08) and (1,0.1) on the graph
slope=0.02/-2
= -0.01 or -1/100
b.area= area of trapizoid+ rectangle
((0.07+0.11)÷2)×4+1×0.07
0.36+0.07
=0.43$
c. the area represent the total cost after 5 hours
PLEASE MARK BRAINLIEST