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Law Incorporation [45]
3 years ago
11

A sample of fluorine gas has a volume of 5.63 L at 14°C and standard pressure. What will be the pressure in atm if the moles of

gas and the temperature do not change but the volume is expanded to 9.21 L?
I know that to solve this, it's (pressure x 5.63L) / 9.21L. Temperature and moles are constant so we can ignore those. But I don't know what's the standard pressure or what it even means
Chemistry
1 answer:
soldier1979 [14.2K]3 years ago
6 0

With standard pressure there is a set list of values. (at STP), most common is 760torr. So whenever you see "at STP" or "at standard temperature pressure" you will use 760torr for pressure. Same thing goes with temperature, if you're not given temp and it says at STP you will use 273K.

For this problem:

You will be using the combined gas law:

(Pressure 1) x (Volume 1) / (Temp. 1) = (Pressure 2) x (Volume 2) / (Temp. 2)

(760torr) x (5.63L) / (287K) = (?) (9.21L) / (287K)

Pressure 2 = 465torr

*Hope this clarifies STP for you! :)

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10. A 2.36-gram sample of NaHCO3 was completely decomposed in an
Airida [17]

Answer:

0.79 g

Explanation:

Let's introduce a strategy needed to solve any similar problem like this:

  • Apply the mass conservation law (assuming that this reaction goes 100 % to completion): the total mass of the reactants should be equal to the total mass of the products.

Based on the mass conservation law, we need to identify the reactants first. Our only reactant is sodium bicarbonate, so the total mass of the reactants is:

m_r=m_{NaHCO_3}=2.36 g

We have two products formed, sodium carbonate and carbonic acid. This implies that the total mass of the products is:

m_p=m_{Na_2CO_3}+m_{H_2CO_3}

Apply the law of mass conservation:

m_r=m_p

Substitute the given variables:

m_{NaHCO_3}=m_{Na_2CO_3}+m_{H_2CO_3}

Rearrange for the mass of carbonic acid:

m_{H_2CO_3}=m_{NaHCO_3}-m_{Na_2CO_3}=2.36 g - 1.57 g=0.79 g

8 0
3 years ago
Calculate total ATP produced from a fatty acid of 32 carbons
emmasim [6.3K]

Answer:

Total number of ATP molecules generated from a 32-carbon fatty acid = 206 ATP molecules

Explanation:

A 32 carbon fatty acid which undergoes complete beta-oxidation assuming that the fatty acid is fully saturated will pass through the beta-oxidation cycle 14 times to produce the following:

15 molecules of acetylCoA, 14 molecules of FADH₂, and 14 molecules of NADH.

Each of the 15 acetylCoA molecules can be further oxidized in the citric acid cycle to yield the following: 15 × 3 NADH; 15 × 1 FADH₂, and 15 ATP molecules from the substrate level phosphorylation occuring at the succinylCoA synthetase catalyzed-reaction.

Total FADH₂ produced = 15 + 14 = 29 molecules of FADH₂

Total NADH produced = 45 + 14 = 59 molecules of NADH

The FADH₂ and NADH will each donate a pair of electrons to the electron transfer flavoprotein and mitochondrial NADH dehydrogenase respectively of the electron transport chain, and about 1.5 and 2.5 molecules of ATP are generated respectively when these electrons are transfered to molecular oxygen.

Thus, number of molecules of ATP generated by 29 molecules of FADH₂ = 1.5 × 29 = 43.5 molecules of ATP.

Number of molecules of ATP generated by 59 molecules of NADH = 2.5 × 59 = 147.5

Sum of ATP generated from FADH₂ and NADH = 43.5 + 147.5 = 191 ATP molecules

Total number of ATP molecules generated = 191 + 15 = 206 ATP molecules

Total number of ATP molecules generated from a 32-carbon fatty acid = 206 ATP molecules

7 0
2 years ago
Compounds like CCl₂F₂ are known as chlorofluorocarbons, or CFCs. These compounds were once widely used as refrigerants but are n
natta225 [31]

Answer: Mass Of CFC that needs to evaporate for the freezing of water = 328.24 g

Explanation: Heat gained by the CFC = Heat lost by water

Heat lost by water = Heat required to take water's temperature to 0°c + Heat required to freeze water at 0°c

Heat required to take water's temperature from 33°c to 0°c = mCΔT

m = 201g, C = 4.18 J/(gK), ΔT = 33

mCΔT = 201 × 4.18 × 33 = 27725.94 J

Heat required to freeze water at 0°c = mL

m = 201g, L = 334 J/g

mL = 201 × 334 = 67134 J

Heat gained by CFC to vaporize = mH = 27725.94 + 67134 = 94859.94 J

H = 289 J/g, m = ?

m × 289 = 94859.9

m = 328.24 g

QED!!

7 0
3 years ago
If you mixed three Dixie cups’ contents together containing 0.05L of 1.0M lemonade, 0.05L of 2.5M lemonade, and 0.05L of 0.5M le
viva [34]

Molarity of the resulting solution will be 1.33 M.

<u>Explanation:</u>

First we have to find the number of moles for each of the solution using the formula, moles = molarity × volume

For cup 1  = 1  M ×0.05 L = 0.05 moles

For cup 2 = 2.5 M × 0.05 L= 0.125 moles

For cup 3 = 0.5 M × 0.05 L = 0.025 moles

Total moles = 0.05 + 0.125 + 0.025  = 0.2 moles

We have to find the total volume as, 0.05 + 0.05 + 0.05 = 0.15 L

Now we have to find the molarity as, moles / volume = 0.2 moles/ 0.15 L = 1.33 M

3 0
2 years ago
1. A chemical equation is balanced when *
lubasha [3.4K]

Answer:1 Answer. A chemical equation is balanced when the number of each kind of atom is the same on both sides of the reaction,,

6 0
2 years ago
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