When lithium nitride, Li3N(s) , is treated with water, H2O(l) , ammonia, NH3(g) , is produced. Predict the formula of the gas pr
1 answer:
Answer:
The formula of the gas produced is, and the balanced equation is :
Explanation:
The chemical reaction between lithium nitride and water gives lithium hydroxide and ammonia gas. The chemical equation of this reaction will be given as:
And when sodium phosphide reacts with water is gives an aqueous solution of sodium hydroxide and hydrogen phosphide gas also called phosphine gas.
The chemical equation of this reaction will be given as:
The formula of the gas produced is, and the balanced equation is :
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Taking into account the reaction stoichiometry and ideal gas law, 0.48144 grams of KClO₃ was decomposed.
<h3>Reaction stoichiometry</h3>In first place, the balanced reaction is:
2 KClO₃ → 2 KCl + 3 O₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- KClO₃: 2 moles
- KCl: 2 moles
- O₂: 3 moles
The molar mass of the compounds is:
- KClO₃: 122.45 g/mole
- KCl: 74.45 g/mole
- O₂: 32 g/mole
Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
- KClO₃: 2 moles ×122.45 g/mole= 244.8 grams
- KCl: 2 moles ×74.45 g/mole= 148.9 grams
- O₂: 3 moles ×32 g/mole= 96 grams
The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:
P×V = n×R×T
where:
- P is the gas pressure.
- V is the volume that the gas occupies.
- T is the temperature of the gas.
- R is the ideal gas constant. The universal constant of ideal gases R has the same value for all gaseous substances.
- n is the number of moles of the gas.
165 mL of oxygen is produced at 30.0 °C and 90.0 kPa. This is, you know:
- P= 90 kPa= 0.888231 atm (being 101.325 kPa= 1 atm)
- V= 165 mL= 0.165 L (being 1000 mL= 1 L)
- n= ?
- R= 0.082
- T= 30 C= 303 K (being 0 C= 273 K)
Replacing in the ideal gas law:
0.888231 atm× 0.165 L = n× 0.082 × 303 K
Solving:
n= (0.888231 atm× 0.165 L)÷ (0.082 × 303 K)
<u><em>n= 0.0059 moles</em></u>
Finally, 0.0059 moles of oxygen is produced at 30 °C and 90 kPa.
<h3>Mass of KClO₃ required</h3>The following rule of three can be applied: If by stoichiometry of the reaction 3 moles of O₂ are produced by 244.8 grams of KClO₃, 0.0059 moles of O₂ are produced by how much mass of KClO₃?
<u><em>mass of KClO₃= 0.48144 grams</em></u>
Finally, 0.48144 grams of KClO₃ was decomposed.
Learn more about
the reaction stoichiometry:
<u>brainly.com/question/24741074</u>
<u>brainly.com/question/24653699</u>
ideal gas law: