Use the formula E=hv, h=plancks constant and v=frequency
use the formula c=v*lambda to find v
the answer will be 2.88*10^-23J
Answer:
heat capacity: "the number of heat units needed to raise the temperature of a body by one degree."
Explanation:
Answer:
1.62 g
Explanation:
Given that:
Concentration of HCN = 0.119 M
Assuming the ka 4.00 × 10⁻¹⁰
The pKa of HCN (hydrocyanic acid) = -log (Ka)
= - log ( 4.00 × 10⁻¹⁰)
= 9.398
pH of buffer = 8.809
Using Henderson Hasselbach equation:
![pH = pKa + log \dfrac{[conjugate\ base ]}{acid}](https://tex.z-dn.net/?f=pH%20%3D%20pKa%20%2B%20log%20%5Cdfrac%7B%5Bconjugate%5C%20%20base%20%5D%7D%7Bacid%7D)
![pH = pKa + log \dfrac{[CN^-]}{[HCN]}](https://tex.z-dn.net/?f=pH%20%3D%20pKa%20%2B%20log%20%5Cdfrac%7B%5BCN%5E-%5D%7D%7B%5BHCN%5D%7D)
![8.809 = 9.398 +log \dfrac{[CN^-]}{[HCN]}](https://tex.z-dn.net/?f=8.809%20%3D%209.398%20%2Blog%20%5Cdfrac%7B%5BCN%5E-%5D%7D%7B%5BHCN%5D%7D)
![log \dfrac{[CN^-]}{[HCN]}= 8.809 - 9.398](https://tex.z-dn.net/?f=log%20%5Cdfrac%7B%5BCN%5E-%5D%7D%7B%5BHCN%5D%7D%3D%208.809%20-%209.398)
![log \dfrac{[CN^-]}{[HCN]}= -0.589](https://tex.z-dn.net/?f=log%20%5Cdfrac%7B%5BCN%5E-%5D%7D%7B%5BHCN%5D%7D%3D%20-0.589)
![\dfrac{[CN^-]}{[HCN]}= 0.2576](https://tex.z-dn.net/?f=%5Cdfrac%7B%5BCN%5E-%5D%7D%7B%5BHCN%5D%7D%3D%200.2576)
[CN^-] = 0.2576[HCN]
[CN^-] = 0.2756 (0.119) L
[CN^-] = 0.033 M
∴
The amount of NaCN (sodium cyanide) is calculated as follows:

= 1.62 g
Answer:
7.56 atm
Explanation:
Boyle's law states that the pressure and volume of a gas are proportional to each other
The formular for Boyle's law is
P1V1=P2V2
According to the question above, the values given are
P1=1.50 atm
P2= ?
V1=12.60 litres
V2= 2.50 litres
Let us make P2 the subject of formular
P2= P1V1/V2
P2= 1.50×12.60/2.50
P2= 18.9/2.50
P2= 7.56 atm
Hence when the volume of a gas is 2.50 litres then it's pressure is 7.56 atm
Chemical because it can not be changed like cutting a piece of paper