Explanation:
The given data is as follows.
, 
Work produced per kJ of heat extracted from hot reservoir = 0.45 kJ = Efficiency
If the device is Carnot cycle then its efficiency will be maximum and its value will be equal to ![[1 - (\frac{T_{c}}{T_{h}} )]](https://tex.z-dn.net/?f=%5B1%20-%20%28%5Cfrac%7BT_%7Bc%7D%7D%7BT_%7Bh%7D%7D%20%29%5D)
Using this relation we will calculate the efficiency as follows.
Efficiency =
= 
= 0.928
Hence, it means that this type of device is possible and the claim is also believable.
0.012 mol of CO₂ can be produced from 3.50 g of baking powder.
<h3>
What is baking powder?</h3>
- Baking powder is a dry chemical leavener composed of carbonate or bicarbonate and a weak acid.
- The addition of a buffer, such as cornstarch, prevents the base and acid from reacting prematurely.
- Baking powder is used in baked goods to increase volume and lighten the texture.
To find how many moles of CO₂ are produced from 1.00 g of baking powder:
The balanced equation is:
- Ca(H₂PO₄)₂(s) + 2NaHCO₃(s) → 2CO₂(g) + 2H₂O(g) + CaHPO₄(s) + Na₂HPO₄(s)
On 3.50 g of baking power:
- mCa(H₂PO₄)₂ = 0.35 × 3.50 = 1.225 g
- mNaHCO₃ = 0.31 × 3.50 = 1.085 g
The molar masses are: Ca = 40 g/mol; H = 1 g/mol; P = 31 g/mol; O = 16 g/mol; Na = 23 g/mol; C = 12 g/mol.
So,
- Ca(H₂PO₄)₂: 40 + 4 × 1 + 31 + 8 × 16 = 203 g/mol
- NaHCO₃: 23 + 1 + 12 + 3 × 16 = 84 g/mol
The number of moles is the mass divided by molar mass, so:
- nCa(H₂PO₄)₂ = 1.225/203 = 0.006 mol
- nNaHCO₃ = 1.085/84 = 0.0129 mol
First, let's find which reactant is limiting.
Testing for Ca(H₂PO₄)₂, the stoichiometry is:
- 1 mol of Ca(H₂PO₄)₂ ---------- 2 mol of NaHCO₃
- 0.006 of Ca(H₂PO₄)₂ -------- x
By a simple direct three rule:
So, NaHCO₃ is in excess.
The stoichiometry calculus must be done with the limiting reactant, then:
- 1 mol of Ca(H₂PO₄)₂ ------------- 2 mol of CO₂
- 0.006 of Ca(H₂PO₄)₂ -------- x
By a simple direct three rule:
Therefore, 0.012 mol of CO₂ can be produced from 3.50 g of baking powder.
Know more about baking powder here:
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The correct question is given below:
Calcium dihydrogen phosphate, Ca(H2PO4)2, and sodium hydrogen carbonate, NaHCO3, are ingredients of baking powder that react with each other to produce CO2, which causes dough or batter to rise: Ca(H2PO4)2(s) + NaHCO3(s) → CO2(g) + H2O(g) + CaHPO4(s) + Na2HPO4(s)[unbalanced] If the baking powder contains 31.0% NaHCO3 and 35.0% Ca(H2PO4)2 by mass: (a) How many moles of CO2 are produced from 3.50 g of baking powder?
Answer:
1. (See explanation)
2. 46. 23 from the mother’s egg and 23 from the father’s sperm.
Explanation:
ok for number one I am not entirely sure, but I am pretty sure that light, chemicals and temperature can all affect which genes get turned on and off. I am not entirely sure if the question is asking about the environment influencing inherited traits in the form of natural selection tho? If that is something you’re seeing right now, it might be a possible answer. But honestly I am not completely sure.
Water (H
2O) is a polar inorganic compound that is at room temperature a tasteless and odorless liquid, which is nearly colorless apart from an inherent hint of blue. It is by far the most studied chemical compound and is described as the "universal solvent" [18][19] and the "solvent of life".[20] It is the most abundant substance on Earth[21] and the only common substance to exist as a solid, liquid, and gas on Earth's surface.[22] It is also the third most abundant molecule in the universe.[21]
Water (H
2O)


NamesIUPAC name
water, oxidane
Other names
Hydrogen hydroxide (HH or HOH), hydrogen oxide, dihydrogen monoxide (DHMO) (systematic name[1]), hydrogen monoxide, dihydrogen oxide, hydric acid, hydrohydroxic acid, hydroxic acid, hydrol,[2] μ-oxido dihydrogen
Identifiers
CAS Number
7732-18-5 
3D model (JSmol)
Interactive image
Beilstein Reference
3587155ChEBI
CHEBI:15377 
ChEMBL
ChEMBL1098659 
ChemSpider
937 
Gmelin Reference
117
PubChem CID
962
RTECS numberZC0110000UNII
059QF0KO0R 
InChI
InChI=1S/H2O/h1H2 
Key: XLYOFNOQVPJJNP-UHFFFAOYSA-N 
SMILES
O
Properties
Chemical formula
H
2OMolar mass18.01528(33) g/molAppearanceWhite crystalline solid, almost colorless liquid with a hint of blue, colorless gas[3]OdorNoneDensityLiquid:[4]
0.9998396 g/mL at 0 °C
0.9970474 g/mL at 25 °C
0.961893 g/mL at 95 °C
Solid:[5]
0.9167 g/ml at 0 °CMelting point0.00 °C (32.00 °F; 273.15 K) [a]Boiling point99.98 °C (211.96 °F; 373.13 K) [6][a]SolubilityPoorly soluble in haloalkanes, aliphaticand aromatic hydrocarbons, ethers.[7]Improved solubility in carboxylates, alcohols, ketones, amines. Miscible with methanol, ethanol, propanol, isopropanol, acetone, glycerol, 1,4-dioxane, tetrahydrofuran, sulfolane, acetaldehyde, dimethylformamide, dimethoxyethane, dimethyl sulfoxide, acetonitrile. Partially miscible with Diethyl ether, Methyl Ethyl Ketone, Dichloromethane, Ethyl Acetate, Bromine.Vapor pressure3.1690 kilopascals or 0.031276 atm[8]Acidity (pKa)13.995[9][10][b]Basicity (pKb)13.995Conjugate acidHydroniumConjugate baseHydroxideThermal conductivity0.6065 W/(m·K)[13]
Refractive index (nD)
1.3330 (20 °C)[14]Viscosity0.890 cP[15]Structure
Crystal structure
Hexagonal
Point group
C2v
Molecular shape
Bent
Dipole moment
1.8546 D[16]Thermochemistry
Heat capacity (C)
75.375 ± 0.05 J/(mol·K)[17]
Std molar
entropy (So298)
69.95 ± 0.03 J/(mol·K)[17]
Std enthalpy of
formation (ΔfHo298)
−285.83 ± 0.04 kJ/mol[7][17]
Gibbs free energy (ΔfG˚)
−237.24 kJ/mol[7]
Answer: The beginning stage you decide to depict the area, or position, of an object.
Explanation: starting point or position
