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Debora [2.8K]
3 years ago
12

A 60-kg motor sits on four cylindrical rubber blocks. Each cylinder has a height of 3 cm and a cross-sectional area of 15 cm2. T

he shear modulus for this rubber is 2.0 MPa. A.) If a sideways force of 300 N is applied to the motor, how far will it move sideways? B.) With what frequency will the motor vibrate back and forth sideways if disturbed?
Physics
2 answers:
Free_Kalibri [48]3 years ago
5 0

Answer:

Part a)

x = 3 mm

Part b)

f = 6.5 Hz

Explanation:

Part a)

As we know that shear modulus is given as

\eta = \frac{F/A}{x/L}

now we have

x = \frac{FL}{\eta A}

here we have

F = 300 N

A = 15 cm^2

L = 3 cm

\eta = 2 \times 10^6 Pa

now we have

x = \frac{300 \times 0.03}{(15 \times 10^{-4})(2\times 10^6)}

x = 3 mm

Part b)

As we know that

F = \frac{\eta A}{L} x

now the frequency of oscillation is given as

f = \frac{1}{2\pi}\sqrt{\frac{k}{m}}

here we know

k = \frac{\eta A}{L}

k = \frac{2\times 10^6 \times (15 \times 10^{-4})}{0.03}

k = 10^5

f = \frac{1}{2\pi}\sqrt{\frac{10^5}{60}}

f = 6.5 Hz

stealth61 [152]3 years ago
3 0
<span>A.) If a sideways force of 300 N is applied to the motor, how far will it move sideways?</span>
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