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4vir4ik [10]
3 years ago
6

If a car has a linear acceleration of 1.8m/s^2 and the radius of its wheels is 0.33m, what is the angular acceleration of the wh

eels? What was the angular displacement of the wheels after one minute?
Physics
2 answers:
Hoochie [10]3 years ago
6 0

Answer:

The angular acceleration of the wheels is 5.46 rad/s²

The angular displacement of the wheels after one minute is 327.6 rad/s

Explanation:

Given;

linear acceleration, a = 1.8m/s²

radius of the wheel, r = 0.33m

The angular acceleration of the wheels is calculated as;

\alpha = \frac{a}{r}

where;

\alpha is angular acceleration

a is linear acceleration of the wheel

r is radius of the wheel

\alpha = \frac{1.8 }{0.33} =5.46 \ rad/s^2

The angular displacement of the wheels after one minute;

ω = αt

Given;

time, t = 1 minutes = 60 seconds

ω = 5.46 x 60

ω = 327.6 rad/s

daser333 [38]3 years ago
4 0

Answer:

5.45rad/s^2

Explanation: Given that

a = 1.8m/s^2

r = 0.33m

a= αr

1.8 = α × 0.33

1.8 = 0.33α

α = 1.8/0.33

α = 5.45rad/s^2

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adell [148]

Answer:

5.565 V

Explanation:

Radius of coil of generator=r=0.14 m

Length of wire=l=10 m

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We have to find the peak emf of the generator.

N=\frac{l}{2\pi r}=\frac{10}{2\pi\times 0.14}=11

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Peak(maximum) induced emf of generator=E_{max}=NBA\omega

Using the formula

E_{max}=11\times 0.24\times 0.062\times 34

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Lapatulllka [165]

Answer:

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