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KatRina [158]
3 years ago
14

Determine whether each of the statements below is true or false, and place it in the appropriate bin. Objects with equal speeds

definitely have equal velocities. If you are given an object's velocity, you can definitely determine its speed. If you know the distance an object travels, and the time it takes to do so, you can determine the object's velocity. If an object moves at constant speed, it must also be moving at constant velocity. If an object moves at constant velocity, it must also be moving at constant speed. Objects with equal velocities definitely have equal speeds.
Physics
1 answer:
lisov135 [29]3 years ago
7 0

Objects with equal speeds definitely have equal velocities. -- FALSE.  For equal velocities, they also have to be going in the same direction.

If you are given an object's velocity, you can definitely determine its speed. -- TRUE.  If you know the velocity, then you know both the object's speed and its direction.

If you know the distance an object travels, and the time it takes to do so, you can determine the object's velocity. -- FALSE. Knowing the distance and time, you can figure out the object's speed.  But if you don't also know the direction it's moving, then you can't say what its velocity is.

If an object moves at constant speed, it must also be moving at constant velocity. -- FALSE.  Besides constant speed, it also needs to move in a straight line to have constant velocity.  If it turns, its velocity changes, even if its speed doesn't.

If an object moves at constant velocity, it must also be moving at constant speed. -- TRUE.  Constant velocity means its speed AND its direction are not changing.

Objects with equal velocities definitely have equal speeds. -- TRUE.  If their velocities are equal, then their speeds are equal AND they're moving in the same direction.

After laboring through this one, I'm wondering if there can possibly be any more ways to say the same thing.

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2 years ago
g a small smetal sphere, carrying a net charge is held stationarry. what is the speed are 0.4 m apart
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Complete Question

A small metal sphere, carrying a net charge q1=−2μC, is held in a stationary position by insulating supports. A second small metal sphere, with a net charge of q2= -8μC and mass 1.50g, is projected toward q1. When the two spheres are 0.80m apart, q2 is moving toward q1 with speed 20ms−1. Assume that the two spheres can be treated as point charges. You can ignore the force of gravity.The speed of q2 when the spheres are 0.400m apart is.

Answer:

The value v_2  =  4 \sqrt{10} \  m/s

Explanation:

From the question we are told that

   The  charge on the first sphere is  q_1  =  2\mu C  =  2*10^{-6} \  C

    The charge on the second sphere is  q_2 =  8 \mu C = 8*10^{-6} \  C

     The  mass of the second charge is m  =  1.50 \  g  =  1.50 *10^{-3} \ kg

      The  distance apart is  d =  0.4 \  m

      The  speed of the second  sphere is  v_1  =  20 \  ms^{-1}

Generally the total energy possessed by when q_2 and  q_1 are separated by 0.8 \  m is mathematically represented

     Q =  KE + U

Here KE   is  the kinetic energy which is mathematically represented as

     KE  =  \frac{1 }{2}  m (v_1)^2

substituting value

     KE  =  \frac{1 }{2}  * ( 1.50 *10^{-3}) (20 )^2

     KE  =  0.3 \  J

And  U is  the  potential  energy which is mathematically represented as

        U  =  \frac{k *  q_1 *  q_2  }{d }

substituting values

       U  =  \frac{9*10^9 *  2*10^{-6} * 8*10^{-6}  }{0.8 }

      U  =  0.18 \  J

So

       Q =  0.3 +  0.18

       Q =  0.48 \  J

Generally the total energy possessed by when q_2 and  q_1 are separated by 0.4 \  m is mathematically represented

         Q_f =  KE_f + U_f

Here KE_f is  the kinetic energy which is mathematically represented as

     KE_f  =  \frac{1 }{2}  m (v_2^2

substituting value

     KE_f  =  \frac{1 }{2}  * ( 1.50 *10^{-3}) (v_2 )^2

     KE_f  =  7.50 *10^{ -4} (v_2 )^2

And  U_f is  the  potential  energy which is mathematically represented as

        U_f  =  \frac{k *  q_1 *  q_2  }{d }

substituting values

       U_f  =  \frac{9*10^9 *  2*10^{-6} * 8*10^{-6}  }{0.4 }

      U_f  =  0.36 \  J

From the law of energy conservation

     Q =  Q_f

So

    0.48 =  0.36 +(7.50 *10^{-4} v_2^2)

   v_2  =  4 \sqrt{10} \  m/s

     

   

6 0
3 years ago
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