Complete Question
A 95 kg clock initially at rest on a horizontal floor requires a 650 N horizontal force to set it in motion. After the clock is in motion, a horizontal force of 560 N keeps it moving with a constant velocity. Find the coefficient of static friction and the coefficient of kinetic friction.
Answer:
The value for static friction is 
The value for static friction is 
Explanation:
From the question we are told that
The mass of the clock is 
The first horizontal force is 
The second horizontal force is 
Generally the static frictional force is equal to the first horizontal force
So
=> 
=>
Generally the kinetic frictional force is equal to the second horizontal force
So
Answer:
a force
Explanation:
Because if we apply force then only an object can slow down, speed up or change direction
The prefix your looking for is centi as in centimeter. I got this answer on google.
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The force of friction is given by:
f = μR, where μ is the friction coefficient and R is the reaction force, which will be equal to the weight.
100 = μ x 130
μ = 0.77
Answer:
A. 
B. 
C. ΔK
Explanation:
From the exercise we know that the car and the truck are traveling eastward. I'm going to name the car 1 and the truck 2
A. Since the two vehicles become entangled the final mass is:
From linear momentum we got that:
B. The change in velocity of both vehicles are:
For the car
For the truck
C. The change in kinetic energy is:
ΔK=
ΔK=
ΔK
