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Anna71 [15]
3 years ago
14

Describe the relationship between air time and range.

Physics
1 answer:
kifflom [539]3 years ago
3 0

Answer: For the angles below 40, The air time and range are directly proportional meaning that if air time increases, the range increases. Like said earlier, the total traveled distance in the x-direction depends on the initial velocity and time.

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1. A diver dives off of a raft - what happens to the diver? The raft? How does this relate to Newton's Third Law?  Action Force:
Natali [406]
The Action Force of this scenario is the pushing force of the Diver. The Reaction Force is the raft pushing back on the diver. 

The Third Law of Motion states that "For every action, there is an equal and opposite reaction." Now when the diver dives off the raft, the raft is also pushing the same amount of force as the diver did as he dives off. The diver will then move forward and the raft on the other hand will move backwards.

The movement of the raft shows the opposite force. It will move backwards depending on how strong the diver will push off on the raft. And the amount of force he pushes on it, the raft will exert the same force so the stronger the force of the diver, the farther he will go because the raft will push him in that same direction as it goes backwards. 
7 0
3 years ago
In 1976, the SR-71A, flying at 20 km altitude (T = –56 0C), set the official jet-powered aircraft speed record of 3530 km/hr (21
Lapatulllka [165]

To solve this problem we will apply the concepts related to the calculation of the speed of sound, the calculation of the Mach number and finally the calculation of the temperature at the front stagnation point. We will calculate the speed in international units as well as the temperature. With these values we will calculate the speed of the sound and the number of Mach. Finally we will calculate the temperature at the front stagnation point.

The altitude is,

z = 20km

And the velocity can be written as,

V = 3530km/h (\frac{1000m}{1km})(\frac{1h}{3600s})

V = 980.55m/s

From the properties of standard atmosphere at altitude z = 20km temperature is

T = 216.66K

k = 1.4

R = 287 J/kg

Velocity of sound at this altitude is

a = \sqrt{kRT}

a = \sqrt{(1.4)(287)(216.66)}

a = 295.049m/s

Then the Mach number

Ma = \frac{V}{a}

Ma = \frac{980.55}{296.049}

Ma = 3.312

So front stagnation temperature

T_0 = T(1+\frac{k-1}{2}Ma^2)

T_0 = (216.66)(1+\frac{1.4-1}{2}*3.312^2)

T_0 = 689.87K

Therefore the temperature at its front stagnation point is 689.87K

6 0
3 years ago
5. Кульки із сталі, чавуну, міді і латуні мають однакові розміри. Яка з них має
Oksanka [162]

Answer:

Sorry, I don't understand this language, sorry dear

4 0
2 years ago
A car moves with an average speed of 75 kmh^-1 from town P to town Q in 2 hours. By using information, you may calculate the dis
-Dominant- [34]

Answer:

patron

Explanation:

 The patron is something or someone who defends some cause or point of view. In the art field, for example, the patron may be considered a sponsor, that is, someone who is known for defending a particular group of people or specific situation.

  The patron is one who advocates, advises and directs. In the military, patrons are heroic figures who are chosen to defend a military unit, for example.

Explanation:

patron

Explanation:

 The patron is something or someone who defends some cause or point of view. In the art field, for example, the patron may be considered a sponsor, that is, someone who is known for defending a particular group of people or specific situation.

  The patron is one who advocates, advises and directs. In the military, patrons are heroic figures who are chosen to defend a military unit, for example.

7 0
1 year ago
Read 2 more answers
A monochromatic light of wavelength 506 nm from a distant source is incident on a single slit 0.075 mm wide. Diffraction pattern
sladkih [1.3K]

Answer:

first minimum distance from the center = 0.417 m m

Explanation:

given,

wavelength (λ) = 506 nm

d = 0.075 mm  = 0.000075 m

tanθ = x /2

d sinθ = m λ

m=1 ( 1 st minimum  )  

0.000075 × sin θ = 506 × 10⁻⁹

sin θ =\dfrac{506 × 10⁻⁹}{0.000075}

sin θ = 0.00675

θ = sin⁻¹(0.00675)

θ = 0.00675

x =  0.000417 m

hence, the first minimum distance from the center = 0.417 m m

5 0
3 years ago
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