The number of mercury atoms required to produce 3.49 L of H2 gas according to the equation would be 1.89 x 
From the balanced equation of the reaction:
2 moles of Hg are required to produce 1 mole of the H2 gas.
3.49 L of H2 gas was produced and the density of the gas is 0.0899 g/L
Recall that: density = mass/volume
Mass of the H2 gas = density x volume
= 3.49 x 0.0899
= 0.3138 g of H2 gas
Mole of 0.3138 g of H2 gas = mass/molar mass
= 0.3138/2
= 0.1569 mole
Since the ratio of Hg to H2 according to the equation is 2:1, it means that the mole of Hg is twice the mole of H2.
Thus, mole of Hg = 0.1569 x 2
= 0.3138 mole
According to Avogadro, 1 mole of a substance = 6.022×10^23
0.3138 mole would be:
0.3138 x 6.022 x 10^23
= 1.89 x
More on the number of atoms in molecules can be found here: brainly.com/question/19036641
Answer:
8.912x10^-18
Explanation:
-dn/dt = pANa/2piMRT
100 g = initial copper
Number of moles = 100/63.546
= 1.5736
Mass of copper left = 100-10.0168
= 89.9832
Moles = 89.9832/63.546
= 1.4160
dn = 1.4160-1.5736
= -0.1576
dt = 2 hrs
A = 3.23mm² = 3.23x10^-6
M = 63.546
T = 0.0821
T = 1508k
Na = 6.023x10²³
When we insert all these into the formula above
We get
P = 8.912x10^-18atm
Answer:
Chemical energy
Explanation:
By the use of electrons and protons from water
Waters boiling point is 100°C and 212°F
Answer:
It is equal to Avogadro's number (NA), namely 6.022 x1023. If we have one mole of water, then we know that it will have a mass of 2 grams (for 2 moles of H atoms) + 16 grams (for one mole O atom) = 18 grams.
Explanation:
The question is not very much clear.
If you are asking for molecules then 1 mole water= 6.023 * 10^23
If you are asking for atoms then 1 mole water= 6.023 * 10^23 * 3
If you are asking for particles then,
So, in your example you would have one mole of water molecules. If you dissociated those water molecules, than you would end up with 2 moles of hydrogen atoms, and one mole of oxygen atoms.
I hope that was helpful!
H=1 proton,1 electron
O=8 protons,8 neutrons and 8 electrons
total particles in one H2O molecule-28
total no. of particles in 1 mole of water- 6.023 * 10^23 * 28
