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Nata [24]
3 years ago
6

1. When the following oxidation-reduction reaction in acidic solution is balanced, what is the

Chemistry
1 answer:
Bogdan [553]3 years ago
5 0

Answer:

2Rb(s) + Sr^+(aq) → 2Rb^+ (aq) + Sr(s)

Explanation:

Rubidium has a more negative reduction potential (-2.98 V) compared to strontium (-2.89 V).

Hence, in a redox reaction involving rubidium and strontium, rubidium will be oxidized while strontium is reduced.

The balanced redox reaction equation is obtained from;

Oxidation half equation;

2Rb(s) ---->2Rb^+(aq) + 2e

Reduction half equation;

Sr^2+(aq) + 2e ----> Sr(s)

Overall reaction equation;

2Rb(s) + Sr^+(aq) → 2Rb^+ (aq) + Sr(s)

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What is the total pressure in atmospheres in a 10.0L vessel containing 2.50 x 10-3 mol H2, 1.00 x 10-3
grigory [225]

Answer:

Total pressure = 16.42× 10⁻⁹atm

Explanation:

Given data:

Moles of H₂ = 2.50 × 10⁻³ mol

Moles of He = 1.00 × 10⁻³ mol

Mass of Ne = 3 × 10⁻⁴ mol

Volume = 10 L

Temperature = 35°C

Total pressure = ?

Solution:

Pressure of hydrogen:

P = nRT / V

P = 2.50 × 10⁻³ mol× 0.0821 atm. L.mol⁻¹ .k⁻¹ × 308 K / 10 L

p = 63.22× 10⁻³  atm. L /10 L

P = 6.3 × 10⁻³atm

Pressure of helium:

P = nRT / V

P = 1.00 × 10⁻³ mol× 0.0821 atm. L.mol⁻¹ .k⁻¹ × 308 K / 10 L

p = 25.29 × 10⁻³ atm. L /10 L

P = 2.53× 10⁻³ atm

Pressure of neon:

P = nRT / V

P = 3 × 10⁻⁴ mol× 0.0821 atm. L.mol⁻¹ .k⁻¹ × 308 K / 10 L

p = 75.86× 10⁻³ atm. L /10 L

P = 7.59× 10⁻³ atm

Total pressure of mixture:

P(mixture)  = pressure of hydrogen + pressure of helium+ pressure of neon

P(mixture)  = 6.3 × 10⁻³atm + 2.53× 10⁻³ atm + 7.59× 10⁻³ atm

P(mixture) = 16.42× 10⁻⁹atm

8 0
3 years ago
A tow truck uses a force of 100 N to pull a car 10 meters. How much work was done?
Rainbow [258]
W = F * s
W = 100 * 10
W = 1000 J

In short, Your Answer would be 1000 Joules

Hope this helps!
8 0
3 years ago
Read 2 more answers
Diazene, N2H2 (also known as diimine), is commonly used as a reagent for organic syntheses. Label each image with the type of
Fittoniya [83]

The first image shown at the left hand side is a pi bond. The other two images show sigma bonds.

In chemistry, a bond results from the overlap of atomic orbitals. This overlap may be end to end (sigma bond) or side by side (pi bond). Having said this, it is easier to decide whether the bonds in the image shown are sigma or bi bonds.

If we label the images; 1,2,3 from left to right, we can see that the overlap in image 1 is side by side. The electron density lies above and below the plane of the bond. This is a pi bond. In images 2 and 3, the overlap occurs in an end to end manner. This is a sigma bond.

Learn more: brainly.com/question/14018074

3 0
2 years ago
What shows the shape and appearance of the arrangement of atoms in a compound?
Lunna [17]
The shape and arrangement in atoms in a compound are lattice patterns as they have high melting and boiling points
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3 years ago
What is a base? chemistry
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The answer is letter B
4 0
3 years ago
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