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Stella [2.4K]
3 years ago
12

Which chemical symbols will complete the equation for this decomposition reaction?

Chemistry
2 answers:
kondaur [170]3 years ago
6 0

Answer:

Decomposition of KI:

2KI → 2K + 2I

Troyanec [42]3 years ago
3 0
2kl_> 2k +2L for a decomposition reaction
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Why wouldn’t a tennis player with two sneakers “bond” to any other tennis players? Why wouldn’t a helium atom with two electrons
aleksklad [387]

Answer:

Explained below.

Explanation:

A tennis player with two sneakers wouldn't bond to any other tennis player because he is already stable and complete with the 2 and doesn't need another players assistance to make him stand well.

However, helium atom with two electrons wouldn't bond to any other atoms because it is stable. This stability arises from the fact that it has two protons and 2 electrons, of which the 2 electrons completely fill its valence shell/outer most shell to make it neutral.

8 0
3 years ago
Iron is ___<br> A, FE<br> B,CU<br> C,K<br> D, CA
Fiesta28 [93]

<em>Answer:</em>

<em>Ello mate ! the answer is super simple it's option "A" Fe</em>

<em>Explanation:</em>

<em>Iron is a chemical element with symbol</em><em> "Fe"</em><em> and atomic number 26. It is a type of metal, that belongs to the first transition series and group 8 of the periodic table. It is by mass the most common element on Earth, forming much of Earth's outer and inner core.</em>

5 0
3 years ago
Read 2 more answers
When you multiply measurements, the answer should only have the same number of significant figures as the measurement with the _
lisov135 [29]

Answer: fewest

Explanation:

3 0
2 years ago
If the half life of iridium-182 is 15 years, how much of a 3 gram sample is left after 2 half-lives?
padilas [110]

Answer:

D. 0.75 grams

Explanation:

The data given on the iridium 182 are;

The half life of the iridium 182, t_{(1/2)} = 15 years

The mass of the sample of iridium, N₀ = 3 grams

The amount left, N(t) after two half lives is given as follows;

N(t) = N_0 \left (\dfrac{1}{2} \right )^{\dfrac{t}{t_{1/2}} }

For two half lives, t = 2 × t_{(1/2)}

∴ t = 2 × 15 = 30

\dfrac{t}{t_{(1/2)}} = \dfrac{30}{15} = 2

\therefore N(t) = 3 \times\left (\dfrac{1}{2} \right )^2 = 0.75

∴ The amount left, N(t) = 0.75 grams

4 0
3 years ago
Thallium has two stable isotopes, 203tl and 205tl. knowing that the atomic weight of thallium is 204.4, which isotope is the mor
Elza [17]
You have to figure out a way to write the two unknown abundances in terms of one variable.

The total abundance is 1 (or 100%). So if you say the abundance for the first one is X then the abundance for the second one has to be 1-X (where X is the decimal of the percentage so say 0.8 for 80%).

203(X) + 205(1-X) = 204.4

Then you just solve for X to get the percentage for TI-203.
And then solve for 1-X to get the percentage for TI-205.

After that the higher percentage would be the most abundant.

203x + 205 - 205x = 204.4
-2x + 205 = 204.4
-2x = -0.6

x = 0.3
1-x = 0.7

Then the TI-205 would have the highest percentage and would be the most abundant.
7 0
3 years ago
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