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3 years ago

Which chemical symbols will complete the equation for this decomposition reaction?

Chemistry

2 answers:

kondaur [170]3 years ago

6 0

Answer:

Decomposition of KI:

2KI → 2K + 2I

Troyanec [42]3 years ago

3 0

2kl_> 2k +2L for a decomposition reaction

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How many lone pairs are on the central atom of a molecule of RnCl4?

Eva8 [605]

My teacher said it is c

3 0

2 years ago

A student obtains the following data: Mass of empty, dry graduated cylinder: 21.577 g Volume added of NaCl solution: 4.602 mL Ma

klasskru [66]

<u>Answer:</u> The density of NaCl solution is 3.930 g/mL

<u>Explanation:</u>

We are given:

Mass of cylinder, $m_1$ = 21.577 g

Mass of NaCl and cylinder combined, M = 39.664 g

Mass of NaCl, $m_2$ = $(M-m_1)=(39.664-21.577)g=18.087g$

To calculate density of a substance, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

We are given:

Mass of NaCl = 18.087 g

Volume of NaCl solution = 4.602 mL

Putting values in above equation, we get:

$\text{Density of NaCl}=\frac{18.087g}{4.602mL}\\\\\text{Density of NaCl}=3.930g/mL$

Hence, the density of NaCl solution is 3.930 g/mL

7 0

2 years ago

Suppose you were to quickly throw a ball in outer space. Would it slow down as quickly in space, as it does in Earth? Explain wh

Sholpan [36]

Answer:It would never stop until something hit the ball, to slow it down.

Explanation:

This is so because there is no gravitational pull in space.

7 0

3 years ago

Need help with this question please.

LenaWriter [7]

The correct answer would be the last one.

6 0

3 years ago

A system gains 687 kJ of heat, resulting in a change in internal energy of the system equal to 156 kJ. How much work is done?

Maslowich

Answer:

w = -531 kJ

1. Work was done by the system.

Explanation:

Step 1: Given data

Heat gained by the system (q): 687 kJ (By convention, when the system absorbs heat, q > 0).

Change in the internal energy of the system (ΔU°): 156 kJ

Step 2: Calculate the work done (w)

We will use the following expression.

ΔU° = q + w

w = ΔU° - q

w = 156 kJ - 687 kJ

w = -531 kJ

By convention, when w < 0, work is done by the system on the surroundings.

4 0

2 years ago