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2 years ago

10

Calculate ΔHrxn for the following reaction: 5C(s) 6H2(g)→C5H12(l) Use the following reactions and given ΔH values: C5H12(l) 8O2(

g)→5CO2(g) 6H2O(g),ΔHC(s) O2(g)→CO2(g),ΔH2H2(g) O2(g)→2H2O(g),ΔH

1 answer:

Setler79 [48]2 years ago

8 0

Answer: its 4xb236.52

Explanation:

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Cssk12.net bookmarks X Courseware G

nexus9112 [7]

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1 year ago

What is the mass of 4.67 mol of Sulfuric Acid (H2SO4)

Ivahew [28]

<h3>Answer:</h3>

458 g H₂SO₄

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

4.67 mol H₂SO₄

<u>Step 2: Identify Conversions</u>

[PT] Molar Mass of H - 1.01 g/mol

[PT] Molar Mass of S - 32.07 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of H₂SO₄ - 2(1.01) + 32.07 + 4(16.00) = 98.09 g/mol

<u>Step 3: Convert</u>

Set up: $\displaystyle 4.67 \ mol \ H_2SO_4(\frac{98.09 \ g \ H_2SO_4}{1 \ mol \ H_2SO_4})$
Multiply/Divide: $\displaystyle 458.08 \ g \ H_2SO_4$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

458.08 g H₂SO₄ ≈ 458 g H₂SO₄

6 0

2 years ago

1. How many particles are present in 800 grams of copper (II) sulfide, CuS? The molar mass of CuS is 95.611 g/mol.

wel

1-5.037077324x10^23

Use these magic triangles they will help you a lot

8 0

2 years ago

Enzymes are described as catalysts, which means that they __________. View Available Hint(s) Enzymes are described as catalysts,

givi [52]

Answer:

increase the rate of a reaction without being consumed by the reaction

Explanation:

Enzymes are biochemical catalysts that increase the rate of chemical reactions.
They increase the rate of a chemical reaction without being consumed by the reaction.
Enzymes increase the rate of chemical reactions by decreasing the activation energy of the reactants.
Catalysts such as enzymes do not affect the free energy change of a chemical reaction (delta G). Therefore, delta G for a catalyzed and non-catalyzed reaction is equal.

6 0

2 years ago

Exercise 2: (7 points)

Marat540 [252]

Answer:

See explanation

Explanation:

I) from the question;

500 × 10^-3 g dissolves in 100ml

xg dissolves in 1000ml

x = 500 × 10^-3 g × 1000ml/100 ml

x= 5 g/L

Mass concentration = molar concentration × molar mass

Molar concentration = Mass concentration/ molar mass

Molar concentration = 5g/L/419 g/mol

Molar concentration = 0.0119 M

ii) To prepare this solution, measure out 500mg with a weighing balance. Transfer the solid to a standard 100 ml volumetric flask. Make up to the 100ml mark with distilled water.

iii) mass concentration of the solution = 50 g/L

Volume of the solution= 100 ml

Mass of the solid = 50 g/L × 100/1000 L

Mass of solid = 5g

This 5g was taken for 10 days, hence a total of 50 g

Since the normal dose of the drug is 40g for ten days, the patient will suffer from kidney problems because he/she has taken the drug above the recommended dosage.

4 0

2 years ago