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attashe74 [19]
3 years ago
14

Guess the song

Chemistry
2 answers:
Amanda [17]3 years ago
5 0
Drivers license, good but depressing song
Alona [7]3 years ago
3 0
Drivers license, good song
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EastWind [94]
Nuetrons+protons. and number 7 is electrons and protons
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3 years ago
A homogenous mixture of two or more substances is known as a(n) Select one: a. element b. compound c. solution d. atom
babymother [125]
The correct answer is c. solution
7 0
3 years ago
A standard gold bar has a mass of 12.4 kg. When the gold bar is placed into a container of water the volume changes by 642 mL. W
AlekseyPX

Answer:

19.3 g/mL

Explanation:

The following data were obtained from the question:

Mass (m) = 12.4 kg

Volume (V) = 642 mL.

Density (D) =.?

Next, we shall convert 12.4 kg to grams. This can be obtained as follow:

1 kg = 1000 g

Therefore,

12.4 kg = 12.4 × 1000

12.4 kg = 12400 g

Therefore, 12.4 kg is equivalent to 12400 g.

Finally, we shall determine the density of the gold as follow:

Density is simply defined as the mass of the substance per unit volume of the substance. It can be represented mathematically as:

Density (D) = mass (m) / volume (V)

D = m/V

With the above formula, the density of gold can easily be obtained as follow:

Mass (m) = 12400 g

Volume (V) = 642 mL.

Density (D) =.?

D = m/V

D = 12400/642

D = 19.3 g/mL

Therefore, the density of hold is 19.3 g/mL

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3 years ago
What is the volume of a balloon if it contains 3.2 moles of helium answer?
GaryK [48]
The volume of the balloon is 77.0 L<span>.</span><span />
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3 years ago
The ratio between the force of sliding friction and the normal force of an object is called _____.
Kitty [74]

Answer: The correct answer is C.

Explanation: Frictional force is the contact force which resists the motion of one surface on another.

Mathematically,

f=\mu N

where,

f = frictional force

\mu = Coefficient of friction

N = normal force acting on a body

We need to find the ratio of force of sliding friction ( which is a type of frictional force) and the normal force acting on an object. This will be equal to coefficient of friction.

\mu=\frac{f}{N}

4 0
3 years ago
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