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nikitadnepr [17]
3 years ago
11

A scientist is investigating the structure of aluminum nitrate, which has the chemical formula Al(NO3)3. Based on the chemical f

ormula, what can the scientist predict about the structure of this molecule?
It has three NO3 groups.

It has three aluminum (Al) atoms.

It has one NO3 group.

It has nine nitrogen (N) atoms.
Chemistry
1 answer:
bekas [8.4K]3 years ago
6 0
The chemical formula of aluminium nitrate is - Al(NO₃)₃
cation is Al³⁺
anion is NO₃⁻
One Al atom binds to three nitrate groups 
the options given are 
2. <span>It has three aluminum (Al) atoms 
this is incorrect as there's only one Al atom 
3. </span><span>It has one NO3 group.
this is incorrect as there are three nitrate groups
4. </span><span>It has nine nitrogen (N) atoms
there are only 3 N atoms therefore this too is incorrect 
</span>therefore the correct answer is - 
It has three NO₃<span> groups


</span>
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Draw the line-bond structure of oleic acid (cis-9-octadecenoic acid), CH3(CH2)7CH=CH(CH2)7COOH, at physiological pH. You do not
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Answer:

Explanation:

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The line-bond structure of the given oleic acid in the question can be found in the attached below.

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a metal forms two oxides. The higher oxide contains 80% metal. 0.72g of the lower oxide gave 0.8g of the higher oxide when oxidi
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Answer:

0.72 g of the lower oxide gave 0.8 g of higher oxide when oxidised. ... Thus, 90g of lower oxide contains as much metal as 100g of higher oxide, i.e., 80g (given). Hence, 80g of metal combines with 10g of oxygen in the lower oxide and 20g of oxygen in the higher oxide.

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For the reaction N2(g) + 3H2(g) 2NH3(g), what will happen if more nitrogen gas is added?
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The reaction will shift toward the products.

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A solution contains 72.0 g of HCI and 468 g of (C6H6). what is the mole fraction of benzene
erica [24]
<span>Molar mass (MM) of benzene C6H6
C = 6 * 12 = 72u
H = 6 * 1 = 6u
MM C6H6 = 72 + 6 = 78 g / mol
Benzene - Molar Mass = 78 g --------- 1 mol
Of A Mix has 468 g -------------- x

78x = 468
X = 468/78
X = 6 moles
 
Molar mass (MM) of Hydrochloric Acid HCl H = 1 * 1 = 1u
CI = 1 * 35 = 35u
MM HCl = 1 + 35 = 36 g / mol
 
Hydrochloric Acid - Molar Mass = 36 g ---------- 1 mol
Of A Mix has 72 g ------------ y

36y = 72
Y = 72/36
Y = 2 moles
 
Thus, a mixture has a total of 8 moles (6 mol + 2 mol).
Dividing One Mole Amount of Each Substance by the Number of Total Mole Amounts, Then we will obtain a Molar Fraction of Each:
Molar fraction make benzene = (6/8) simplify 2 = 3/4
Molar Fraction to make Hydrochloric Acid = (2/8) = simplify 2 = 1/4

Note:. The sum of the molar fractions of the always give goes 1, we have: 3/4 + 1/4 = 1
 

ANSWER: 
</span>\boxed{\frac{3}{4}}
4 0
3 years ago
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