Answer:
2.60 g of H₂ and 20.8 g of O₂ are produced in the decomposition of 23.44 g of water
Explanation:
Water decomposition is:
2H₂O → 2H₂ + O₂
We convert the mass of water, to moles:
23.44 g . 1 mol/18 g = 1.30 moles
Ratio is 2:2 with hydrogen and 2:1 with oxygen. Let's make rules of three:
2 moles of water can produce 2 moles of hydrogen gas and oxygen gas
Then, 1.30 moles will produce:
(1.30 . 2) /2 = 1.30 moles of H₂
(1.30 . 1) /2 = 0.65 moles of O₂
We convert the moles to mass
1.30 moles of H₂ . 2g / 1mol = 2.60 g of H₂
0.65 moles of O₂ . 32 g / 1 mol = 20.8 g of O₂
Newton’s is how you convert kilograms.
First, we write the reaction for CH3OH combustion
CH3OH+3/2O2--->CO2+2H2O
for 1 mole of methanol, we get 1 mole of CO2, therefore for 5,25 moles of methanol we will get 5,25 moles of CO2
The substance is lipid substance
There are 1.73 moles in 178 grams of Na2SO4
