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valkas [14]
3 years ago
14

Write the formula two atom of iron and three atoms of oxygen​

Chemistry
1 answer:
34kurt3 years ago
5 0

Answer:

Fe2O3 is the formula this is your correct answer

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Which particles that make up an atom are involved in nuclear reactions?.
cestrela7 [59]
Basically nuclear reactions need to involve protons and neutrons and changes in them. So it should be particles within the nucleus. Aka protons and neutrons.
6 0
2 years ago
What is the hydroxide ion concentration of a solution whose pOH is 6.42?
Sergeeva-Olga [200]

Answer : The hydroxide ion concentration of a solution is, 3.8\times 10^{-7}M

Explanation :

As we know that:

pH : It is defined as the negative logarithm of hydrogen ion concentration.

Mathematically,

pH=-\log [H^+]

Similarly,

pOH : It is defined as the negative logarithm of hydroxide ion concentration.

Mathematically,

pOH=-\log [OH^-]

Given:

pOH = 6.42

6.42=-\log [OH^-]

[OH^-]=3.8\times 10^{-7}M

Therefore, the hydroxide ion concentration of a solution is, 3.8\times 10^{-7}M

7 0
3 years ago
At what temperature (in K) will 3.5 moles of gas occupy 2.7 L at 1.5 atm? HELP PLEASE!
Vesnalui [34]

3.5 moles of a gas will occupy 2.7 L at 1.5 atm at a temperature of 14.1K

IDEAL GAS LAW:

  • The temperature of a gas can be calculated using the ideal gas law equation:

PV = nRT

Where;

  1. P = pressure (atm)
  2. V = volume (L)
  3. n = number of moles (mol)
  4. R = gas law constant (0.0821 Latm/molK)
  5. T = temperature (K)

  • According to this question, P = 1.5atm, V = 2.7L, n = 3.5moles, T = ?

  • 1.5 × 2.7 = 3.5 × 0.0821 × T

  • 4.05 = 0.28735T

  • T = 4.05 ÷ 0.28735

  • T = 14.1K

  • Therefore, 3.5 moles of a gas will occupy 2.7 L at 1.5 atm at a temperature of 14.1K

Learn more at: brainly.com/question/13821925?referrer=searchResults

6 0
3 years ago
A fat is composed, in part, of long chains of carbon and hydrogen. This fat as a molecular
IgorLugansk [536]

Answer:

C_{54}H_{102}O_6

Explanation:

Hello!

In this case, since the molar mass of the empirical formula is:

MM_{empircal}=9*12.01+17*1.01+16.00=141.26g/mol

Thus, the ratio of the molecular to the empirical formula is:

\frac{847g/mol}{141.26g/mol} =6.0

Thus, the molecular formula is six times the empirical formula:

C_{54}H_{102}O_6

Best regards!

8 0
3 years ago
Can someone help me balance this chemical equation?<br><br> CO2(g) + H2O(l) -&gt; C6H12O6(aq) + O2
hram777 [196]
It becomes:
6CO2 + 6H2O -> C6H12O6 + 6O2
8 0
3 years ago
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