Group 1a elements (the first column on the left side of the Periodic table) always release one electron to form positive ions with a charge of +1. Group 7a nonmetals (the <em>second to the last </em>column on the right side- the rightmost column are the noble gases) always desire to gain one electron to form negative ions with a charge of -1.
Since their charges are equal and opposite, they will always combine in a 1:1 ratio.
When solid carbon reacts with oxygen gas to produce carbon dioxide gas. the deltaH (enthalpy change ) value is negative .DeltaH would be on the product side of the equation.
<h3>What is enthalpy change? </h3>
In a thermodynamic system, energy is measured by enthalpy. Enthalpy is a measure of a system's overall heat content and is equal to the system's internal energy plus the sum of its volume and pressure.
Knowing whether q is endothermic or exothermic allows one to characterise the relationship between q and H. An endothermic reaction is one that absorbs heat and demonstrates that heat from the environment is used in the reaction, hence q>0 (positive). For the aforementioned equation, under constant pressure and temperature, if q is positive, then H will also be positive. In a similar manner, heat is transferred to the environment when it is released during an exothermic reaction. Thus, q=0 (negative). Therefore, if q is negative, H will also be negative.
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Of course 10% sucrose solution
sorry if im wrong
The element strontium (atomic number = 38) has four naturally-occurring isotopes. They are: Isotope / Percent Abundance / Mass (amu) Sr-84 / 0.56% / 83.9134 Sr-86 / 9.86% / 85.9093 Sr-87 / 7.00% / 86.9089 Sr-88 / 82.58% / 87.9056 The first thing to do is to convert all of the percentages to decimal fractions. To do that just move the decimal point two places to the left. Be careful, though...if the decimal is already at the front of the number you STILL have to move it two places. Add leading zeroes as necessary. 0.56% becomes 0.0056 9.86% becomes 0.0986 7.00% becomes 0.0700 82.58% becomes 0.8258 Next multiply each of the decimal fractions by the mass of each isotope. 0.0056 x 83.9134 = 0.47 0.0986 x 85.9093 = 8.47 0.0700 x 86.9089 = 6.08 0.8258 x 87.9056 = 72.59 Finally add the results to find the average atomic mass. 0.47 + 8.47 + 6.08 + 72.59 = 87.61 amu This agrees closely with the listed atomic mass for strontium, so I know I probably did my work correctly. I hope that helps
