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3 years ago

Help please. The combustion of pentane, C5H12, occurs via the reaction

1 answer:

4 0

If I were you, I'd try to go with this one : $[(6)(-241.8)+(5)(-393.5)]-[-35.1] =-481.6$ . I think that is a solution you have to find. Just use the sum of standard enthalpies of products and of reactants. Hope you will find it helpful!

You might be interested in

A) 24 g B) 36 g C) 48 g D) 60 g

Hitman42 [59]

Answer:

I'm not sure if this right because i've only taken one year of Chemistry but the answer I got was

A. 24 g

5 0

2 years ago

A mixture that results when substances dissolve to form a homogeneous mixture

MrRa [10]

A mixture that results when substances dissolve to form a homogeneous mixture is a solution.

3 0

3 years ago

2 C4H10 + 13 O2--> 8 CO2 + 10 H2O

AleksAgata [21]

Answer:

4.14 x 10²⁴ molecules CO₂

Explanation:

2 C₄H₁₀ + 13 O₂ --> 8 CO₂ + 10 H₂O

To find the number of CO₂ molecules, you need to start with 100 grams of butane (C₄H₁₀), convert to moles (using the molar mass), convert to moles of CO₂ (using coefficients from equation), then convert to molecules (using Avagadro's number). The molar mass of C₄H₁₀ is calculated using the quantity of each element (subscript) multiplied by the number on the periodic table. The ratios should be arranged in a way that allows for units to be cancelled.

4(12.011g/mol) + 10(1.008 g/mol) = 58.124 g/mol C₄H₁₀

100 grams C₄H₁₀ 1 mol C₄H₁₀ 8 mol CO₂
-------------------------- x ---------------------- x ---------------------
58.124 g 2 mol C₄H₁₀

6.022 x 10²³ molecules
x ------------------------------------ = 4.14 x 10²⁴ molecules CO₂
1 mol CO₂

7 0

2 years ago

Hellllpppppppp helppppppppp

mixas84 [53]

Answer :

Charles's Law : It is defined as the volume is directly proportional to the temperature of the gas at constant pressure and number of moles.

Mathematically,

$V\propto T$

Boiling water bath Cool bath 1 Cool bath 2

Temperature (⁰C) 99 17 2

Temperature (K)(T) 273+99=372 273+17=290 273+2=275

Volume of water 0.0 27.0 34.0

in cool flask (mL)

Volume of water= 135.8 135.8 135.8

Air in flask (mL)

Volume of air 135.8 108.8 101.8

in cool flask (V)

$\frac{V}{T}$ $\frac{135.8}{372}=0.365$ $\frac{108.8}{290}=0.375$ $\frac{101.8}{275}=0.370$

The graph volume versus temperature for a gas is shown below.

3 0

2 years ago

If 185 mg of acetaminophen were obtained from a tablet containing 350 mg of acetamino- phen, what would be the weight percentage

Alex73 [517]

Percentage recovery gives us an idea of the amount of pure substance recovered after the chemical reaction. Percentage recovery can be more than 100 % or less than 100 %. Usually, in any experiment performed the weight percentage recovery will be less than 100. Percent recovery values greater than 100 show that the recovered compound is contaminated.

Amount of acetaminophen initially taken = 350 mg

Amount of acetaminophen obtained after recovery =185 mg

$Weight percentage recovery =\frac{mass recovered}{mass originally taken}*100$

= $\frac{185 mg}{350 mg}*100$

= 52.9%

8 0

3 years ago