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3 years ago

Help please. The combustion of pentane, C5H12, occurs via the reaction

1 answer:

4 0

If I were you, I'd try to go with this one : $[(6)(-241.8)+(5)(-393.5)]-[-35.1] =-481.6$ . I think that is a solution you have to find. Just use the sum of standard enthalpies of products and <span>of reactants. Hope you will find it helpful!</span>

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a propane torch is lit inside a hot air balloon during preflight preparations to inflate the balloon. which condition of the gas

earnstyle [38]

Answer:

The pressure remains constant

Explanation:

this is an example in charles law where as the temperature increases so does the volume.

5 0

3 years ago

Read 2 more answers

Identify which subatomic particles match each of these descriptions. One of the descriptions describes two particles. Make sure

Advocard [28]

Explanation:

protons have a relative charge of +1, they are located in the nucleus and the carry a positive charge

the electrons are negatively charged and have a charge of -1 . They are found orbiting on the shells .the electrons have a negligible mass of 1 / 1840

the neutrons have no charge they are located in the nucleus of an atom .

5 0

3 years ago

Which of the following is not present in skeletal structures?

cupoosta [38]

Answer:

cartilage or soft tissue? you didn't give options :/

Explanation:

6 0

3 years ago

What is the mass in grams of 6.12 x 10^20 molecules of caffeine, C8H10N4O2?

baherus [9]

$6,02*10^{23} \ \ \ \ \ \ \rightarrow \ \ \ \ \ 194,2g\\
6,12 * 10^{20} \ \ \ \ \ \ \rightarrow \ \ \ \ \ x\\\\
x=\frac{6,12*10^{20}*194,2g}{6,02*10^{23}}\approx197*10^{-3}g=0,197g$

6 0

3 years ago

Assume the hydrolysis of ATP proceeds with ΔG′° = –30 kJ/mol. ATP + H2O → ADP + Pi Which expression gives the ratio of ADP to AT

Andru [333]

Answer:

$6.14\cdot 10^{-6}$

Explanation:

Firstly, write the expression for the equilibrium constant of this reaction:

$K_{eq} = \frac{[ADP][Pi]}{ATP}$

Secondly, we may relate the change in Gibbs free energy to the equilibrium constant using the equation below:

$\Delta G^o = -RT ln K_{eq}$

From here, rearrange the equation to solve for K:

$K_{eq} = e^{-\frac{\Delta G^o}{RT}}$

Now we know from the initial equation that:

$K_{eq} = \frac{[ADP][Pi]}{ATP}$

Let's express the ratio of ADP to ATP:

$\frac{[ADP]}{[ATP]} = \frac{[Pi]}{K_{eq}}$

Substitute the expression for K:

$\frac{[ADP]}{[ATP]} = \frac{[Pi]}{K_{eq}} = \frac{[Pi]}{e^{-\frac{\Delta G^o}{RT}}}$

Now we may use the values given to solve:

$\frac{[ADP]}{[ATP]} = \frac{[Pi]}{K_{eq}} = \frac{[Pi]}{e^{-\frac{\Delta G^o}{RT}}} = [Pi]e^{\frac{\Delta G^o}{RT}} = 1.0 M\cdot e^{\frac{-30 kJ/mol}{2.5 kJ/mol}} = 6.14\cdot 10^{-6}$

7 0

4 years ago