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Nat2105 [25]
3 years ago
13

F(x)=4(x-1)^2-1 axis of symmetry

Mathematics
1 answer:
Levart [38]3 years ago
6 0
The vertex of this parabola has coordinates (1,-1).
The axis symmetry goes trough the vertex. The equation of the axis of symmetry is x=1.
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Hello! Could y’all please explain why this is Decay and not growth?
svetlana [45]

Answer:

This is an Exponential Decay

Step-by-step explanation:

A = 1200(0.85)⁶

The above expression is an Exponential Decay because 0.85 is less than 1

The formula for Exponential Decay

= y = a (1 - r)^t

We equate both equation together

Where

a = 1200

1 - r = 0.85

t = 6

Solving for r

1 - r = 0.85

r = 1 - 0.85

r = 0.15

Converting to Percentage

r = 15% decay rate

3 0
3 years ago
Tim measures the length of four grasshoppers in his backyard: 5/4 cm, 7/4 cm, 9/4 cm, and 3/4 cm. What is the average length.​
katrin [286]

Answer:6

Step-by-step explanation: add up all the fractions. The answer will be 24/4. Divide 24/4 equals 6.

6 0
3 years ago
Please someone help me solve this i dpnt know the answer​
kozerog [31]
<h2><u>Answer With Explanation:</u></h2>

<u>Firstly, let's start with <XOZ: =55°</u>

We know that <ZOQ is 70° and angles on a line add up to 180° so we do 180-70=110 110 divided by 2 = 55 so the 2 angles (XOZ & XOP are 55)

<u>Secondly, <OMN, <MON & <ONM = All are 60°</u>

These 2 angles are joined to create an equilateral triangle which always adds up to 180°

So, there are 3 points to this triangle, therefore we divide 180 by 3 which is 60. The angles are 60°

<u>Thirdly, <QON: =55°</u>

This angle lies on the line XON which needs to add up to 180°

As we worked out before, <XOZ was 55°

So, <ZOQ was already given as 70°

We then do 55+70=125 then 180-125=55°

<QON is 55°

(I'm only in Grade 9 LOL)

4 0
2 years ago
What is the slope of the linear function..........​
Sergio [31]

Answer:

-1

Step-by-step explanation:

slope: change in y divided by change in x

y2-y1/x2-x1

-11-(-5)/4-(-2)

-11+5/4+2

-6/6

-1

5 0
3 years ago
The medians $AD$, $BE$, and $CF$ of triangle $ABC$ intersect at the centroid $G$. The line through $G$ that is parallel to $BC$
Flauer [41]
G divides each median in the ratio of 2 to 1 (the longer side goes from G to the angle) triangle AMN is similar to triangle ABC (why?) AMN is a scaled version of ABC (by a factor of ⅔) its area should be scaled by (⅔)^2
6 0
3 years ago
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