Answer:
bye hooking plugs up to it to amp it up
Answer:
the reduction in the heat gain is 2.8358 kW
Given that;
Shaft outpower of a motor = 75 hp = ( 75 × 746 ) = 55950 W
Efficiency of motor = 91.0% = 0.91
High Efficiency of the motor = 95.4% = 0.954
now, we know that, efficiency of motor is defined as; = /
where is the electric input given to the motor
so
= /
we substitute
= 55950 W / 0.91
= 61483.5 W
= 61.4835 kW
now, the electric input given to the motor due to increased efficiency will be;
= /
we substitute
= 55950 W / 0.954
= 58647.79 W
= 58.6477 kW
so the reduction of the heat gain of the room due to higher efficiency will be;
Q = -
we substitute
Q = 61.4835 kW - 58.6477 kW
Q = 2.8358 kW
Therefore, the reduction in the heat gain is 2.8358 kW
Explanation: i hope this answer your question if this is wrong or correct please let me know.also no trying to be rude but can you sent me like a thanks?
Answer:
exergy = 33.39 kW
Explanation:
given data
thermal energy reservoir T2 = 1500 K
heat at a rate = 150,000 kJ/h = 
kW = 41.67 kW
environment temperature T1 = 25°C = 298 K
solution
we get here maximum efficiency that is reversible efficiency is express as
reversible efficiency = 1 - 
...............1
reversible efficiency = 1 - 
reversible efficiency = 0.80133
and
the exergy of this supplied energy that is
exergy = efficiency × hat supply ................2
exergy = 0.80133 × 41.67 kW
exergy = 33.39 kW
Answer:
A
Explanation:
i just answered it on my test
Answer:
before wheel is put on it should be looked at for damage and a sound or ring test should be done to check for cracks, to test the wheel it should be tapped with a non metallic instrument (I looked it up)
