Answer:
Explanation:
There are three points in time we need to consider. At point 0, the mango begins to fall from the tree. At point 1, the mango reaches the top of the window. At point 2, the mango reaches the bottom of the window.
We are given the following information:
y₁ = 3 m
y₂ = 3 m − 2.4 m = 0.6 m
t₂ − t₁ = 0.4 s
a = -9.8 m/s²
t₀ = 0 s
v₀ = 0 m/s
We need to find y₀.
Use a constant acceleration equation:
y = y₀ + v₀ t + ½ at²
Evaluated at point 1:
3 = y₀ + (0) t₁ + ½ (-9.8) t₁²
3 = y₀ − 4.9 t₁²
Evaluated at point 2:
0.6 = y₀ + (0) t₂ + ½ (-9.8) t₂²
0.6 = y₀ − 4.9 t₂²
Solve for y₀ in the first equation and substitute into the second:
y₀ = 3 + 4.9 t₁²
0.6 = (3 + 4.9 t₁²) − 4.9 t₂²
0 = 2.4 + 4.9 (t₁² − t₂²)
We know t₂ = t₁ + 0.4:
0 = 2.4 + 4.9 (t₁² − (t₁ + 0.4)²)
0 = 2.4 + 4.9 (t₁² − (t₁² + 0.8 t₁ + 0.16))
0 = 2.4 + 4.9 (t₁² − t₁² − 0.8 t₁ − 0.16)
0 = 2.4 + 4.9 (-0.8 t₁ − 0.16)
0 = 2.4 − 3.92 t₁ − 0.784
0 = 1.616 − 3.92 t₁
t₁ = 0.412
Now we can plug this into the original equation and find y₀:
3 = y₀ − 4.9 t₁²
3 = y₀ − 4.9 (0.412)²
3 = y₀ − 0.83
y₀ = 3.83
Rounded to two significant figures, the height of the tree is 3.8 meters.
mark me the brainiest here
average speed (in km/h) of a car stuck in traffic that drives 12 kilometers in 2 hours.
Answer:
The overview of the given scenario is explained in explanation segment below.
Explanation:
- The inception of cavitation, that further sets the restriction for high-pressure and high-free operation, has always been the matter of substantial experimental study over the last few generations.
- Cavitation inception would be expected to vary on the segment where the local "PL" pressure mostly on segment keeps falling to that are below the "Pv" vapor pressure of the fluid and therefore could be anticipated from either the apportionment of the pressure.
⇒ A cavitation number is denoted by "σ" .
Answer:
t = 1456.8 sec
Explanation:
given data:
contant k = 2.60*10^{-6}
rate of crystallization is 0.0013 s-1
rate of transformation is given by
use specifies value to solve 
it is ime required for 50% tranformation
Avrami equation is given by
n = 1.88
second degree of recrystalization may be determine by rearranging original avrami equation
![t = [\frac{-ln(1-y)}{k}]^{1/n}](https://tex.z-dn.net/?f=t%20%3D%20%5B%5Cfrac%7B-ln%281-y%29%7D%7Bk%7D%5D%5E%7B1%2Fn%7D)
for 90%completion
![t = [\frac{-ln(1-0.9)}{2.60*10^{-6}}]^{1/1.88}](https://tex.z-dn.net/?f=t%20%3D%20%5B%5Cfrac%7B-ln%281-0.9%29%7D%7B2.60%2A10%5E%7B-6%7D%7D%5D%5E%7B1%2F1.88%7D)
t = 1456.8 sec
