In the following code, determine the values of the symbols here and there. Write the object code in hexadecimal. (Do not predict
1 answer:
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Answer:
A)
- Q ( kw ) for vapor = -1258.05 kw
- Q ( kw ) for liquid = -1146.3 kw
B )
- Q ( kj ) for vapor = -1258.05 kJ
- Q ( KJ ) for liquid = - 1146.3 KJ
Explanation:
Given data :
45.00 % mole of methane
55.00 % of ethane
attached below is a detailed solution
A) calculate - Q(kw)
- Q ( kw ) for vapor = -1258.05 kw
- Q ( kw ) for liquid = -1146.3 kw
B ) calculate - Q ( KJ )
- Q ( kj ) for vapor = -1258.05 kJ
- Q ( KJ ) for liquid = - 1146.3 KJ
since combustion takes place in a constant-volume batch reactor
Answer:
(a) The velocity of the collar = 1.624er-15.54eo in/s
(b) the acceleration of the collar=-49.94er-9.74eo in/s²
(c)the acceleration of collative rod =-3.284er in/s²
Explanation:
Check attachment for calculation
