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The hybridization of the C atom in CH₂Br₂ is sp3
When bonding, the orbitals "s" and "p" from C atoms interact to form hybridized orbitals. If the C atom has 4 sigma bonds, as is the case in CH₂Br₂, there are 4 hybridized orbitals required, so 1 "s" orbital and 3 "p" orbitals hybridize to form an sp3 hybrid orbital. This orbital has tetrahedral geometry and the bond angle is 109,5 °.
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Answer:
The sample will dissolve in more than 1 minute.
Explanation:
In order to answer this question, we have to consider several significant aspects:
- temperature is directly proportional to kinetic energy, that is, the greater the temperature, the greater the kinetic energy. Since kinetic energy measures velocity of the particles, this means that the greater the temperature, the greater the velocity of the individual ions of potassium phosphate;
- we may conclude from the first fact that the number of collisions in a given amount of time will then increase due to an increase in velocity;
- it also follows that the greater the temperature, the faster our salt dissolves due to an increase in the number of successful collisions.
This means that at a lower temperature, the sample will dissolve in a longer period of time.
Answer: The metal is Calcium.
Explanation:
To calculate the specific heat of substance during the reaction.

where,
q = heat absorbed = 789.75 J
c = specific heat of metal = ?
m = mass of substance = 18.0 g
= final temperature - initial temperature = 
Now put all the given values in the above formula, we get:


As specific heat is characteristic of each metal and thus the metal is calcium which has specific heat of 
Answer:
Explanation:
The measurement <em>1246g</em> shows four figures. To show this measurement to <em>three signficant figures</em> you must change the last digit to 0 and round properly.
To report the measurement 1246g to three significant figures you must replace the last digit (the 6) with 0 and round the previous one (the 4) to the closest integer: 1250 is closest to 1246 than 1240, so the correct rounding is 1250.
In an integer number, the zeros after the last none zero digit are not sginificant figures; that is why the zero in 1250 g is not significant and this number has just three significant figures.