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Pie
3 years ago
5

What mass of carbon is present in 1.4*x10^20 molecules of sucrose?

Chemistry
1 answer:
Alenkinab [10]3 years ago
4 0

No of moles of Carbon, C = mass/ molar mass.  
 Molar mass of carbon = 12.0107. We only have to calculate the no of moles
of carbon to obtain carbon's mass. .  
 From Sucrose chemical formula C12H22O11 we know that there are 12
carbon atoms. 
 So there are 1.4x10^(20) x12 = 16.8 x 10^20 carbon atoms. 
 We will use avogardo's number to find out the number of carbon molecules
in the compound. 
 From Avogadro's no. One mole of any substance equals to 6.022140857
atoms. 
 
 So X mole contains 16.8 * 10^(20) carbon atom 
 (16.8x10^20 carbon atoms)/6.022 x10^23 particles/mol = 0.00279 mols 
 The molar mass of carbon is 12.0107g/mol so we'll multiply to get the mass:
0.00279 mols x 12 = 0.03348.
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Answer:

The entropy change for a real, irreversible process is equal to <u>zero.</u>

The correct option is<u> 'c'.</u>

Explanation:

<u>Lets look around all the given options -:</u>

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(b) equal to the entropy change for the same process performed reversibly ONLY if the process can be reversed at all. Since , the change is same as well as opposite too . Therefore , this statement is also not true .

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(d) impossible to tell. This option is invalid , thus incorrect .

<u>Hence , the correct option is 'c' that is zero.</u>

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