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Svetradugi [14.3K]
3 years ago
9

How many electrons does nitrogen (N) need to gain to have a stable outer electron shell

Chemistry
2 answers:
earnstyle [38]3 years ago
7 0
It need "3 electrons" to have a stable electronic configuration. 

'cause it has 5 electrons in it's outer shell & every atom needs 8 electrons. So, it requires 3 more!

Hope this helps!
dem82 [27]3 years ago
4 0

Answer: 3 more electrons

Explanation: Generally elements with inert gas configuration are more stable. It is also called as Octet rule.

It tells that, elements which have electrons equal to atomic number of inert gases (2,8,10,18,36 etc) in their valency shell are exceptionally stable.

Here in our case, nitrogen has atomic number-7, 1s2 2s2 2p3

Here N has 5 electrons in valency shell , hence it needs 3 more electrons to get octet configuration.

So answer is 3 Electrons

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How reactive is an atom of Sodium(Na) and why?
s344n2d4d5 [400]
3rd one:
it is very reactive because it does not have a full Valence shell.

this is because it's in group 1 so it has one electron in its outer shell, and it wants to have a full outer shell ( which it can gain by losing the electron in a reaction).

Hope this helps :)
5 0
3 years ago
If a car travels 400.0 meters in 20.0 seconds, how fast is it going?<br> m/s<br> Please help me
Viefleur [7K]

Answer:

20m/s.

Explanation:

8 0
3 years ago
2c4H10 +13O2 —&gt;8CO2+10H2O to find how many moles of oxygen would react with 4.3 mol C4H10
Elena-2011 [213]

Answer:

\large\boxed{\text{28 mol of O$_{2}$}}

Explanation:

             2C₄H₁₀ + 13O₂ ⟶ 8CO₂ + 10H₂O

n/mol:      4.3  

13 mol of O₂ react with 2 mol of 2C₄H₁₀

\text{Moles of O}_{2} = \text{4.3 mol C$_{4}$H$_{10}$} \times \dfrac{\text{13 mol O}_{2}}{\text{2 mol C$_{4}$H$_{10}$}} = \textbf{28 mol O}_{2}\\\\\text{The reaction requires $\large\boxed{\textbf{28 mol of O$_{2}$}}$}

5 0
3 years ago
A solution of ammonia has a pH of 11.8. What is the concentration of OH– ions in the solution?
Basile [38]

Answer:

The answer is 2.20 M

Explanation:

This is because ammonia has a pH of 11.8 and if you take 14-11.8 it equals 2.2 so the answer is 2.20 M

6 0
3 years ago
Read 2 more answers
The ph of a 0.55 m aqueous solution of hypobromous acid, hbro, at 25.0 °c is 4.48. what is the value of ka for hbro?
gladu [14]
Hbro  dissociate  as  follows
HBro--->  H+  +  BrO-
  Ka=  (H+)(BrO-)  /  HBro
 PH  =  -log (H+)
therefore (H+)  =  10^-4.48= 3.31  x10^-5
ka is  therefore= ( 3.31  x 10^-5)^2/0.55=1.99  x10^-9
6 0
3 years ago
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