Find the total area the regular pyramid. T. A. =
2 answers:
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Three consecutive numbers are x, x+1 and x+2.
Four times the first integer is 4x
The sum of the second and third is (x+1)+(x+2)=2x+3.
So, we have
Subtract 2x from both sides:
Divide both sides by 2:
So, you can't have three consecutive integers such that four times the first is 18 more than the sum of the other two: the three numbers would be 10.5, 11.5, 12.5.
In fact, you have
and
The distance between two point:
L=sqrt[(1-(-2))^2+(0-3)^2]=sqrt(18)=3sqrt(2) - <span>magnitude
</span>About <span>direction. Angle is 45</span>°, both point are on the line y=-x+1
L=sqrt[(1-(-2))^2+(0-3)^2]=sqrt(18)=3sqrt(2) - <span>magnitude
</span>About <span>direction. Angle is 45</span>°, both point are on the line y=-x+1
Do recall that squaring and the *radical sign* cancel each other out... like so:(
)
= a
When you put it that way, it isn't enough :P
()= a
(
)=?
so you start with
()= 
8x+1=25 <-- subtract 1 to both sides
8x=24 <- divide 8 to both sides
x= 3
To find out if it's an extraneous solution ask yourself: It mustn't result in a radical that I like to call... 'illegal'. Plug it into the radicand 8x+1 and make sure you get something that is not a negative number.... so, DO you get a negative number when you plug in x = 3 into the radicand?
(extraneous solution is a invalid solution)
x=3 not extraneous
When you put it that way, it isn't enough :P
(
(
so you start with
(
8x+1=25 <-- subtract 1 to both sides
8x=24 <- divide 8 to both sides
x= 3
To find out if it's an extraneous solution ask yourself: It mustn't result in a radical that I like to call... 'illegal'. Plug it into the radicand 8x+1 and make sure you get something that is not a negative number.... so, DO you get a negative number when you plug in x = 3 into the radicand?
(extraneous solution is a invalid solution)
x=3 not extraneous