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3 years ago

Find the total area the regular pyramid. T. A. =

Mathematics

2 answers:

drek231 [11]3 years ago

8 0

Answer:

$T.A = 16\sqrt{3}$

lorasvet [3.4K]3 years ago

5 0

Answer:

T.A. = 16√3 units²

Step-by-step explanation:

∵ The total area = the area of the four faces

∵ The four faces are equilateral triangles with side length 4

∵ Area of the equilateral Δ = 1/4 s² √3

∴ T.A. = 4 × 1/4 × 4² × √3 = 16√3 units²

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3 years ago

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Orlov [11]

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3 years ago

Which number is a solution of a² +4= 6a – 1? 07 6 7 8

LuckyWell [14K]

Answer:

a=1 or a=5

Step-by-step explanation:

$a^{2}$ +4=6a−1

Step 1: Subtract 6a-1 from both sides.

$a^{2}$ +4−(6a−1)=6a−1−(6a−1)

$a^{2}$ −6a+5=0

Step 2: Factor left side of equation.

(a−1)(a−5)=0

Step 3: Set factors equal to 0.

a−1=0 or a−5=0

a=1 or a=5

(is it helpful rate me according to that

Thank You:-)

6 0

3 years ago

I know that real numbers consist of the natural or counting numbers, whole numbers, integers, rational numbers and irrational nu

ra1l [238]

The imaginary unit $i$ belongs to the set of complex numbers, denoted by $\mathbb C$ . These numbers take the form $a+bi$ , where $a,b$ are any real numbers.

The set of real numbers, $\mathbb R$ , is a subset of $\mathbb C$ , where each number in $\mathbb R$ can be obtained by taking $b=0$ and letting $a$ be any real number.

But any number in $\mathbb C$ with non-zero imaginary part is not a real number. This includes $i$ .

"is it possible that i can use an imaginary number for a real number"

I'm not sure what you mean by this part of your question. It is possible to represent any real number as a complex number, but not a purely imaginary one. All real numbers are complex, but not all complex numbers are real. For example, 2 is real and complex because $2=2+0i$ .

There are some operations that you can carry out on purely imaginary numbers to get a purely real number. A famous example is raising $i$ to the $i$ -th power. Since $i=e^{i\pi/2}$ , we have