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3 years ago

Find the total area the regular pyramid. T. A. =

Mathematics

2 answers:

drek231 [11]3 years ago

8 0

Answer:

$T.A = 16\sqrt{3}$

lorasvet [3.4K]3 years ago

5 0

Answer:

T.A. = 16√3 units²

Step-by-step explanation:

∵ The total area = the area of the four faces

∵ The four faces are equilateral triangles with side length 4

∵ Area of the equilateral Δ = 1/4 s² √3

∴ T.A. = 4 × 1/4 × 4² × √3 = 16√3 units²

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blsea [12.9K]

Hi, here is the solution...

f(x) = 2 $x^{2}$ + x - 3 and g(x) = x + 2

(f.g)(x) = f(x). g(x)

= (2 $x^{2}$ + x - 3) *(x + 2)

Now use the distributive property, we get

= (2 $x^{2}$ + x - 3)x + 2(2 $x^{2}$ +x -3)

= 2 $x^{3}$ + $x^{2}$ -3x + 4 $x^{2}$ + 2x - 6

Now combine the like terms.

= 2 $x^{3}$ +5 $x^{2}$ -1x -6 [-3x +2x = -1x = -x]

(f.g)(x) = 2 $^{3}$ +5 $x^{2}$ -x -6

That's it. Thank you :)

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Step-by-step explanation:

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