Answer:a lightbulb burning
Explanation:
Apex
Answer:
sp3 - 1,2,13,16,18,19
sp2- 3,4,5,6,7,8,9,10,11,12,14,15,17
sp- 0
Explanation:
Hybridization is the idea that atomic orbitals fuse to form newly hybridized orbitals, which in turn, influences molecular geometry and bonding properties (Chemlibretexts).
Carbon atoms that are singly bonded are sp3 hybridized, carbon atoms that are doubly bonded are sp2 hybridized while carbon atoms that are triply bonded are sp hybridized.
Sp3 hybridized atoms have a tetrahedral geometry, sp2 hybridized atoms have a trigonal planar geometry while an sp hybridized atom has a linear geometry.
The hybridization state of each atom in the compound has been shown in the answer section.
It runs from 0 to 14. (A)
It is based off the -log [H+] where [H+] is the concentration of the Hydrogen ions.
The statement "Although sulfuric acid is a strong electrolyte, an aqueous solution of H₂SO₄ contains more HSO₄⁻ ions than SO₄²⁻ ions is <u>True.</u> This is best explained by the fact that H₂SO₄ <u>is a diprotic acid where only the first hydrogen completely ionizes.</u>
Why?
H₂SO₄ is a diprotic acid. That means that it has <u>two hydrogen ions</u> to give to the solution. The two dissociation reactions are shown below:
H₂SO₄ + H₂O → HSO₄⁻ + H₃O⁺
HSO₄⁻ + H₂O ⇄ SO₄²⁻ + H₃O⁺
As the arrows show, the first dissociation is complete, meaning that all the sulfuric acid that is present initially is dissociated into HSO₄⁻ and H₃O⁺. However, the second dissociation is incomplete, and it's actually an equilibrium with an acid constant (Ka)of 1.2×10⁻².
That means that if the initial concentration of H₂SO₄ was 1M, the concentration of HSO₄⁻ is going to be 1M as well, but <u>the concentration of SO₄²⁻ is going to be much less than 1M</u>, according to the dissociation constant.
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