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Valentin [98]
3 years ago
15

One mole of carbon, sulfur, and aluminum, respectively. Which jar contains the most atoms?

Chemistry
2 answers:
forsale [732]3 years ago
7 0

Answer:

sulphur cuz its weight is 32.065g

Explanation:

this is correct

plz mark me brainliest

givi [52]3 years ago
3 0

Answer:

Each jar contains the same number of atoms.

Explanation:

One mole of any element will contain 6.0221 × 1023 atoms, regardless of its identity. Since each jar contains exactly one mole, each jar has the same number of atoms.

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What are physical properties of Cobalt Silicate ?
seraphim [82]

Answer:

Some of the properties of cobalt silicate include:

It occurs as a crystal with red- violet type colour.

The shape of the cobalt silicate crystal is orthorhombic.

The molecular weight of cobalt silicate is 209.95.

The melting temperature of Cobalt Silicate is 1618 degrees Celsius.

The density of Cobalt Silicate is 4.63 grams per centimetre cube.

Cobalt Silicate can serve as a semi-conductor.

8 0
3 years ago
what is the pH of a solution that results when 0.010mol HNO3 is added to 500.ml of a solution that is 0.10M in aqueous ammonia a
WARRIOR [948]

Answer : The  

pH of a solution is, 8.56

Explanation : Given,

K_b=1.8\times 10^{-5}

Concentration of ammonia (base) = 0.10 M

Concentration of ammonium nitrate (salt) = 0.55 M

First we have to calculate the value of pK_b.

The expression used for the calculation of pK_b is,

pK_b=-\log (K_b)

Now put the value of K_b in this expression, we get:

pK_b=-\log (1.8\times 10^{-5})

pK_b=5-\log (1.8)

pK_b=4.7

Now we have to calculate the pOH of buffer.

Using Henderson Hesselbach equation :

pOH=pK_b+\log \frac{[Salt]}{[Base]}

Now put all the given values in this expression, we get:

pOH=4.7+\log (\frac{0.55}{0.10})

pOH=5.44

The pOH of buffer is 5.44

Now we have to calculate the pH of a solution.

pH+pOH=14\\\\pH+5.44=14\\\\pH=14-5.44\\\\pH=8.56

Thus, the pH of a solution is, 8.56

8 0
3 years ago
Pls tell me how to solve this!
Anna35 [415]

Answer:

12 seconds

Explanation:

Time taken by 50cm³ of oxygen to diffuse from pinhole

= 1 minute = 60 seconds

⠀

⠀

\textsf{ Rate of oxygen} \sf (O_2) = \frac{50}{60}

⠀

⠀

⠀

<u>Let</u><u> </u><u>time</u><u> </u><u>taken</u><u> </u><u>by</u><u> </u><u>5</u><u>0</u><u>c</u><u>m</u><u>³</u><u> </u><u>of</u><u> </u><u>hydrogen</u><u> </u><u>to</u><u> </u><u>diffuse</u><u> </u><u>from</u><u> </u><u>pinhole</u><u> </u><u>=</u><u> </u><u>t</u><u> </u><u>seconds</u>

⠀

⠀

\textsf {Rate of hydrogen } \sf(H_2) =  \frac{50}{t}

⠀

⠀

⠀

According to the formula

\sf \frac{Rate  \: of  \: hydrogen(H_2)}{Rate \:  of \:  oxygen(O_2) }  =   \sqrt{ \frac{Molar \: mass \: of \:  O_2}{Molar  \: mass \: of \: H_2} }

⠀

⠀

\large  \sf  \frac{50}{t}  \div  \frac{50}{60}  =  \sqrt{ \frac{\cancel{32}\small 16}{\cancel2} }  \\  \\  \sf   \large \frac{ \cancel{50}}{t}  \times  \frac{60}{ \cancel{50}}  =  \sqrt{16}  \\  \\  \sf   \large \frac{60}{t}  = 4 \\  \\  \sf \large  \frac{ \cancel{60} \:  \small12}{ \cancel4}  = t \\  \\    \large \underline{ \boxed{ \tt t = 12 \: seconds}}

⠀

⠀

⠀

<h3><u>Henceforth</u><u>,</u><u> </u><u>the</u><u> </u><u>time</u><u> </u><u>taken</u><u> </u><u>by</u><u> </u><u>5</u><u>0</u><u>c</u><u>m</u><u>³</u><u> </u><u>of</u><u> </u><u>hydrogen</u><u> </u><u>to</u><u> </u><u>diffuse</u><u> </u><u>is</u><u> </u><u>1</u><u>2</u><u> </u><u>seconds</u><u>.</u><u> </u></h3>

⠀

⠀

<h2>Thank you!</h2>
8 0
2 years ago
Draw a Lewis structure for the following molecules on scratch paper. Then give the number of bonds between the C and N in each.
Yuliya22 [10]

Refer to the attachments

6 0
3 years ago
A mixture of pure agcl and pure agbr is found to contain 60.94% ag by mass. what are the mass percents of cl and br in the mixtu
Annette [7]
First step is to calculate the mass of Ag in each compound separately:
From the periodic table: 
molar mass of Ag is 107.87 gm
molar mass of Cl is 35.45 gm
molar mass of Br is 79.9 gm
For AgCl, mass % of Ag = [107.87/143.32] x 100 = 75.26%
For AgBr, mass % of Ag = [107.87/187.77] x 100 = 57.45 %

Second step is to calculate the mass % of each compound in the mixture:
Assume mass % of AgCl is y and that of AgBr is (1-y) as the total percentage is 100% or 1
0.6094 = 0.7526 y + 0.5745 (1-y)
y = 0.8716
This means that the mixture is almost 87% AgCl and 13% AgBr
The mass % of chlorine and bromine together is (100%-60.94%) which is 39.06%
mass % of chlorine = (1-0.6094)(0.8716) x 100 = 34.044%
mass % of bromine = 39.04 - 34.044 = 5.056%
7 0
3 years ago
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