Find equation where line passes through (7,8) and perpendicular to line y=8
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Given:
In a right triangle, the measure of one acute angle is 12 more than twice the measure of the other acute angle.
To find:
The measures of the 2 acute angles of the triangle.
Solution:
Let x be the measure of one acute angle. Then the measure of another acute is (2x+12).
According to the angle sum property, the sum of all interior angles of a triangle is 180 degrees. So,
Divide both sides by 3.
The measure of one acute angle is 26 degrees. So, the measure of another acute angle is:
Therefore, the measures of two acute angles are 26° and 64° respectively.
For this case we have that by definition, the equation of a line of the slope-intersection form is given by:
Where:
m: It's the slope
b: It is the cut-off point with the y axis
While the point-slope equation of a line is given by:
Where:
m: It's the slope
It is a point through which the line passes
In this case we have a line through:
(8,4) and (0,2)
Therefore, its slope is:
Its point-slope equation is:
Then, we manipulate the expression to find the equation of the slope-intersection form:
Therefore, the cut-off point with the y-axis is
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