<h2>ANSWER: </h2><h2>_____________________________________</h2><h2>TYPES OF CHEMICAL REACTIONS:</h2>
There are two types of Reactions,
<h3>
Endothermic Reactions: </h3>
Endothermic reactions are the type chemical reaction in which the reactants absorb heat energy from the surroundings. The energy of reactants is more than the energy of product
<h3>Exothermic Reactions: </h3>
Exothermic reactions are the type of chemical reactions in which release of energy takes place in the form of heat or light. In an exothermic reaction, energy is released. The energy of the products is less than the energy of the reactants.
<h2>_____________________________________</h2><h3 /><h3>In Question number 5,</h3>
The key word is "RELEASE". The reaction in which energy is released is the Exothermic reaction thus the Option B that is EXOTHERMIC REACTION is correct.
<h2>_____________________________________</h2><h3 /><h3>In Question number 6</h3>
It is asking that which process stores the energy that means it is asking which process undergoes endothermic reaction. The answer is Option C that is PHOTOSYNTHESIS is correct.
<h3>__________________________________________________</h3><h3>WHY PHOTOSYNTHESIS?</h3>
Because, sunlight is being absorbed during the reaction and according to the definition of endothermic reaction if heat is being absorbed it is termed as an endothermic reaction.
<h3>__________________________________________________</h3><h3 /><h3 />
Answer:
43.83 nC
Explanation:
We know Q = ε₀Ψ where Q = charge enclosed by the cubic box, ε₀ = permittivity of free space = 8.854 × 10⁻¹² F/m and Ψ = net electric flux through cubic box = 4950 Nm²/C
So, substituting the values of the variables into the equation, we have
Q = ε₀Ψ
= 8.854 × 10⁻¹² F/m × 4950 Nm²/C
= 43827.3 × 10⁻¹² C = 4.38273 × 10⁻⁸ C
= 43.8273 × 10⁻⁹ C
= 43.8273 nC
≅ 43.83 nC
Answer: a) when the cross section is doubled the resultant resistence is a half. This means the thicker wire have half resistence than the thinner wire.
Explanation: In order to explain this behaviur we have to consider the expresion for the resistence which is given by:
where L and A are the length and the cross section for the wire, respectively.
From this expresssion we can conclude the above, this means
R=εo*L/A if A is now 2A we have
R' = εo*L/2*A= R/2
The first one is C!
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34 + 3.7395 = 37.7395
The answer is 38.
The answer is written to two significant figures because the smallest given number of significant figure is 2.