The student who did the most work is student 2 with 2500 Joules.
<u>Given the following data:</u>
To determine which of the students did the most work:
Mathematically, the work done by an object is given by the formula;
<u>For </u><u>student 1</u><u>:</u>
Work done = 600 Joules
<u>For </u><u>student 2</u><u>:</u>
Work done = 2500 Joules.
Therefore, the student who did the most work is student 2 with 2500 Joules.
Read more: Read more: brainly.com/question/13818347
Answer:
The force exerted by the block on the floor is 38.4 Newtons
Explanation:
The given parameters are;
The area of the box in contact with the floor, A = 2.4 m²
The pressure exerted by the block on the floor, P = 16 N/m²
The force exerted by the box on the floor is given as follows;
∴ F = P × A
From the question, P = 16 N/m², and A = 2.4 m²
∴ F = 16 N/m² × 2.4 m² = 38.4 N
The force exerted by the block on the floor, F = 38.4 N.
Answer:
(a)
(b)
Explanation:
Vx = 1.6 x 10^6 m/s
Vy = 2.6 x 10^6 m/s
Bx = 0.024 T
By = - 0.14 T
charge of electron, q = - 1.6 x 10^-19 C
charge of proton, q = 1.6 x 10^-19 C
(a) Force on electron is given by
Substituting the values
(b) Force on proton is given by
Substituting the values
The De Broglie's wavelength of a particle is given by:
where
is the Planck constant
p is the momentum of the particle
In this problem, the momentum of the electron is equal to the product between its mass and its speed:
and if we substitute this into the previous equation, we find the De Broglie wavelength of the electron:
So, the answer is True.