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Trava [24]
3 years ago
7

Student 1 lifts a box with a force of 500 N and sets it on a tabletop 1.2 m high. Student 2 pushes an identical box up a 5 m ram

p from the floor to the top of the same table. Which student did the MOST work?
Physics
2 answers:
Troyanec [42]3 years ago
7 0

The student who did the most work is student 2 with 2500 Joules.

<u>Given the following data:</u>

  • Force 1 = 500 Newton
  • Distance 1 = 1.2 meter
  • Force 2 = 500 Newton
  • Distance 2 = 5 meter

To determine which of the students did the most work:

Mathematically, the work done by an object is given by the formula;

Work\;done = Force \times distance

<u>For </u><u>student 1</u><u>:</u>

Work\;done = 500 \times 1.2

Work done = 600 Joules

<u>For </u><u>student 2</u><u>:</u>

Work\;done = 500 \times 5

Work done = 2500 Joules.

Therefore, the student who did the most work is student 2 with 2500 Joules.

Read more: Read more: brainly.com/question/13818347

Simora [160]3 years ago
4 0

Answer:student 2 did the most work

Explanation:student 2 did more work because he pushed it up 5 m instead of 1.2.

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Therefore,

Solving Eq.1 for acceleration,
 
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<span>Now applying Newton's 2nd law of motion,
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3 years ago
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Let's replace

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Let's calculate

    F = 1.6 10⁻¹⁹ 28 10³ / 1.4 10⁻²

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b) For this part we can use kinematics

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Acceleration can be found with Newton's second law

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Let's calculate the speed

       v = √ (2 3,516 10¹⁷ 1.4 10⁻²)

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Explanation:

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Isolating  T:

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Finally:

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Explanation:

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