Answer:
There are no acceptable descriptions at all on that list of choices.
Answer:-
.
Solution:- Aspartame is a artificial sweetener with molecular formula
and it's molecular mass is 294.3 gram per mol.
We have been given with 4.50 mg of aspartame and asked to calculate the moles. For mass to moles conversion we divide the given mass in grams by molar mass.
Since, the mass is given in mg, we need to convert it to g first.
1 mg = 0.001 g
So, 
= 0.00450 g
Now let's calculate the moles on dividing the grams by molar mass as:

= 
Hence,
are present in 4.50 mg of aspartame.
Answer:
The answer to your question is 35.4527 g
Explanation:
Data
Cl-35 abundance = 75.77 % mass Cl-35 = 34.9688
Cl-37 abundance = 24.23 % mass Cl-37 = 36.9659
Process
1.- Convert the percents to decimals
75.77% = 75.77/100 = 0.7577
24.23% = 24.23/100 = 0.2423
2.- Find the atomic weight
Average atomic weight = Abundance 1 x Mass Cl-35 +
Abundance 2 x Mass Cl-37
Substitution
Average atomic weight = (0.7577)(34.9688) + (0.2423 x 36.9659)
Simplification
Average atomic weight = 26.4959 + 8.9568
Result
Average atomic weight = 35.4527 g
Answer: The volume in the balloon at the higher altitude is 260 L
Explanation:
The combined gas equation is,
where,
= initial pressure of gas = 760 torr
= final pressure of gas = 511 torr
= initial volume of gas = 233 L
= final volume of gas = ?
= initial temperature of gas =
= final temperature of gas =
Now put all the given values in the above equation, we get:
The volume in the balloon at the higher altitude is 260 L