Answer:
q = 3.6 10⁵ C
Explanation:
To solve this exercise, let's use one of the consequences of Gauss's law, that all the charge on a body can be considered at its center, therefore we calculate the electric field on the surface of a sphere with the radius of the Earth
r = 6 , 37 106 m
E = k q / r²
q = E r² / k
q = 
q = 4.5 10⁵ C
Now let's calculate the charge on the planet with E = 222 N / c and radius
r = 0.6 r_ Earth
r = 0.6 6.37 10⁶ = 3.822 10⁶ m
E = k q / r²
q = E r² / k
q = 
q = 3.6 10⁵ C
P = m*v
7.5 = m*15
m = 7.5/15 = 0.5 kg
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Answer: increases
Explanation:
Because the relationship between hand d is counter
Answer:
r = 0.37 m
Explanation:
Use Coulomb's law to solve for r:
F = kq1q2/r^2
---> r^2 = kq1q2/F
= (8.99×10^9)(5.6×10^-4)(-2.1×10^-4)/(-7.7×10^3)
= 0.1373 m^2
or r = 0.37 m
