Answer:
total number of electron in 1 litter is 3.34 × electron
Explanation:
given data
mass per mole = 18 g/mol
no of electron = 10
to find out
how many electron in 1 liter of water
solution
we know molecules per gram mole is 6.02 × molecules
no of moles is 1
so
total number of electron in water is = no of electron ×molecules per gram mole × no of moles
total number of electron in water is = 10 × 6.02 × × 1
total number of electron in water is = 6.02× electron
and
we know
mass = density × volume ..........1
here we know density of water is 1000 kg/m
and volume = 1 litter = 1 × m³
mass of 1 litter = 1000 × 1 ×
mass = 1000 g
so
total number of electron in 1 litter = mass of 1 litter ×
total number of electron in 1 litter = 1000 ×
total number of electron in 1 litter is 3.34 × electron
Nearly equal the output work is greater than the input work because of friction.All machines use some amount of input work to overcome friction.The only way to increase the work output is to increase the work you put into the machine.You cannot get more work out of a machine than you put into it.
Answer:
ac = 3.92 m/s²
Explanation:
In this case the frictional force must balance the centripetal force for the car not to skid. Therefore,
Frictional Force = Centripetal Force
where,
Frictional Force = μ(Normal Force) = μ(weight) = μmg
Centripetal Force = (m)(ac)
Therefore,
μmg = (m)(ac)
ac = μg
where,
ac = magnitude of centripetal acceleration of car = ?
μ = coefficient of friction of tires (kinetic) = 0.4
g = 9.8 m/s²
Therefore,
ac = (0.4)(9.8 m/s²)
<u>ac = 3.92 m/s²</u>
Explanation:
Given that,
Terminal voltage = 3.200 V
Internal resistance
(a). We need to calculate the current
Using rule of loop
Where, E = emf
R = resistance
r = internal resistance
Put the value into the formula
(b). We need to calculate the terminal voltage
Using formula of terminal voltage
Where, V = terminal voltage
I = current
r = internal resistance
Put the value into the formula
(c). We need to calculate the ratio of the terminal voltage of voltmeter equal to emf
Hence, This is the required solution.
That just depends on the mass of the object and I think it will accelerate forwards