A mini rail gun made of a copper rod of mass m and radius r rests on two parallel copper rails that are a distance L apart and o
1 answer:
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Answer:
the final speed of object A changed by a factor of = 0.58
the final speed of object B changed by a factor of = 1.29
Explanation:
Given;
kinetic energy of object A, = 27 J
let the mass of object A =
then, the mass of object B =
work done on object A = -18 J
work done on object B = -18 J
let be the initial speed
let be the final speed
For object A;
Thus, the final speed of object A changed by a factor of = 0.58
To obtain the change in the final speed of object B, apply the following equations.
Thus, the final speed of object B changed by a factor of = 1.29
Answer:
D = -4/7 = - 0.57
C = 17/7 = 2.43
Explanation:
We have the following two equations:
First, we isolate C from equation (2):
using this value of C from equation (3) in equation (1):
<u>D = - 0.57</u>
Put this value in equation (3), we get:
<u>C = 2.43</u>