All categories

3 years ago

Date Page 2. A bicycle of 15kg is moving with the velocity of 10m/s. calculate the kinetic energy.

Physics

1 answer:

QveST [7]3 years ago

3 0

Answer:

$\boxed {\boxed {\sf 750 \ J}}$

Explanation:

Kinetic energy is the energy an object possesses due to motion. It is calculated using the following formula.

$E_k= \frac{1}{2} mv^2$

In this formula, m is the mass and v is the velocity.

The bicycle has a mass of 15 kilograms and a velocity of 10 meters per second.

m= 15 kg
v= 10 m/s

Substitute the values into the formula.

$E_k= \frac {1}{2} (15 \ kg)(10 \ m/s)^2$

Solve the exponent.

(10 m/s)²= 10 m/s * 10 m/s = 100 m²/s²

$E_k= \frac{1}{2} (15 \ kg)( 100 \ m^2/s^2)$

Multiply all the values together.

$E_k= \frac{1}{2} ( 1500 \ kg*m^2/s^2)$

$E_k= 750 \ kg*m^2/s^2$

1 kilogram meter squared per second squared is equal to 1 Joule. Therefore, our answer of 750 kg*m²/s² is equal to 750 J.

$E_k= { 750 \ J$

The kinetic energy of the bicycle is 750 Joules.

You might be interested in

A person throws a ball from height of 6 feet with an initial vertical velocity of 48 feet per second. Use the vertical motion mo

True [87]

Explanation:

Recall the equation for time is distance divided by speed. Here you can use that to solve for "t".

7 0

3 years ago

An hydrogen molecule consists of two hydrogen atoms whose total mass is 3.3×10−27 kg and whose moment of inertia about an axis p

dlinn [17]

Answer:

$6.9631\times 10^{-11}\ m$

Explanation:

I = Moment of inertia = $4\times 10^{-48}\ kg m^2$

m = Mass of two atoms = 2m = $3.3\times 10^{-27}\ kg$

r = distance between axis and rotation mass

Moment of inertia of the system is given by

$I=mr^2\\\Rightarrow I=2mr^2\\\Rightarrow 4\times 10^{-48}=3.3\times 10^{-27}\times r^2\\\Rightarrow r=\sqrt{\frac{4\times 10^{-48}}{3.3\times 10^{-27}}}\\\Rightarrow r=3.48155\times 10^{-11}\ m$

The distance between the atoms will be two times the distance between axis and rotation mass.

$d=2r\\\Rightarrow d=2\times 3.48155\times 10^{-11}\\\Rightarrow d=6.9631\times 10^{-11}\ m$

Therefore, the distance between the two atoms is $6.9631\times 10^{-11}\ m$

3 0

4 years ago

An observer (O) spots a plane (P) taking off from a local airport and flying at a 29° angle horizontal to her line of sight and

nikklg [1K]

B. 10,824 feet
is the right answer
tan 26 = 6000/x
x = 10824 ft

7 0

3 years ago

What is the speed of a bobsled whose distance-time graph indicates that it traveled 100 m in 25 s?

larisa86 [58]

As per the question, the distance travelled by bobsled [s] = 100 m

The time taken by the bobsled to travel that distance [t] = 25 s

We are asked to calculate the speed of the bobsled.

The speed of the bobsled is calculated as -

$speed\ =\ \frac{distance}{time}$

$v\ =\ \frac{s}{t}$

$=\frac{100\ m}{25\ s}$

$=\ 4\ m/s$

Hence, the correct answer to the question is A. 4 m/s.

8 0

3 years ago

A uniform rod rotates in a horizontal plane about a vertical axis through one end. The rod is 3.46 m long, weighs 12.8 N, and ro

Mkey [24]

Answer:

a. Rotational inertia: 5.21kgm²

b. Magnitude of it's angular momentum: 123.32kgm²/s

Explanation:

Length of the rod = 3.46m

Weight of the rod = 12.8 N

Angular velocity of the rod= 226 rev/min

a. Rotational Inertia (I) about its axis

The formula for rotational inertia =

I = (1/12×m×L²) + m × ( L ÷ 2)²

Where L = length of the rod

m = mass of the rod

Mass of the rod is calculated by dividing the weight of the rod with the acceleration due to gravity.

Acceleration due to gravity = 9.81m/s²

Mass of the rod = 12.8N/ 9.81m/s²

Mass of the rod = 1.305kg

Rotational Inertia =

(1/12× 1.305 × 3.46²)+ 1.305 ( 3.46÷2)²

Rotational Inertia = 1.3019115 + 3.9057345

Rotational Inertia = 5.207646kgm²

Approximately = 5.21kgm²

b. The magnitude of the rod's angular momentum about the rotational axis is calculated as

Rotational Inertia about its axis × angular speed of the rod.

Angular speed of the rod is calculated as= (Angular velocity of the rod × 2π)/60

= (226×2π) /60

= 23.67 rad/s

Rotational Inertia = 5.21kgm²

The magnitude of the rod's angular momentum about the rotational axis

= 5.21kgm²× 23.67 rad/s

= 123.3207kgm²/s

Approximately = 123.32kgm²/s

7 0

4 years ago

Date Page 2. A bicycle of 15kg is moving with the velocity of 10m/s. calculate the kinetic energy. ​

Date Page 2. A bicycle of 15kg is moving with the velocity of 10m/s. calculate the kinetic energy.