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Nataliya [291]
3 years ago
15

HELP ME PLZ I NEED TO PASS

Physics
2 answers:
Varvara68 [4.7K]3 years ago
6 0

Answer:

50 newtons

Explanation:

subtract directions

ipn [44]3 years ago
5 0

Answer:

D. 50 N

Explanation:

The 2 forces of the cart will counteract each other because they are being pushed in opposite directions. The 150 N will counteract the 150 N on the other side. But since there's an extra 50 N on the left, it will push 50 N to the right. The 2 150 N will do nothing because they are pushing in opposite directions. For example, if two people are pushing something in the opposite direction with the exact same force, the pushed object won't move.

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146 million kilometers or 92.96 million miles away!

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An object is thrown straight up with a velocity, in ft/s, given by v(t)= -32t + 83, where t is in seconds, from a height of 46 f
____ [38]
<h2>a) Initial velocity = 83 ft/s</h2><h2>b) Object's maximum speed = 99.4 ft/s</h2><h2>c) Object's maximum displacement = 153.64 ft</h2><h2>d) Maximum displacement occur at t = 2.59 seconds.</h2><h2>e) The displacement is zero when t = 5.70 seconds</h2><h2>f) Object's maximum height = 153.64 ft</h2>

Explanation:

We have velocity

             v(t)= -32t + 83

Integrating

              s(t) = -16t²+83t+C

At t = 0 displacement is 46 feet

              46 = -16 x 0²+83 x 0+C

                 C = 46 feet

So displacement is

              s(t) = -16t²+83t+46

a) Initial velocity is

                 v(0)= -32 x 0 + 83 = 83 ft/s

       Initial velocity = 83 ft/s

b) Maximum velocity is when the object reaches ground, that is s(t) = 0 ft

Substituting

             0 = -16t²+83t+46

             t = 5.70 seconds

Substituting in velocity equation

           v(t)= -32 x 5.70 + 83 = -99.4 ft/s

           Object's maximum speed = 99.4 ft/s

c) Maximum displacement is when the velocity is zero

   That is

                 -32t + 83 = 0

                       t = 2.59 s

Substituting in displacement equation

                s(2.59) = -16 x 2.59²+83 x 2.59+46 = 153.64 ft

Object's maximum displacement = 153.64 ft

d) Maximum displacement occur at t = 2.59 seconds.

e) Refer part b

   The displacement is zero when t = 5.70 seconds

f) Same as option d

   Object's maximum height = 153.64 ft

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Answer:

true

Explanation:

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The answer is B. the rotation of the earth on its axis.


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A package is dropped from an airplane flying at an altitude of 69.2 m with a velocity of 1.40 x 10^2 km/h. Calculate the horizon
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