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zhenek [66]
3 years ago
7

Given two angle meausres and the length of sides betweeen them, sean is asked to construct a triangle. how will he determine the

other two sides?
Mathematics
2 answers:
creativ13 [48]3 years ago
6 0

Answer:       C   by extending each given angle from the endpoint until the segments intersect across from the given side

Step-by-step explanation:

BARSIC [14]3 years ago
3 0

Explanation:

When Sean draws rays at the specified angles from the ends of the given side, they will cross (intersect) at a point that determines the length of the other two sides.

That is why the two angles and the side between them (ASA) are sufficient to specify a triangle, ensuring congruence or similarity, as the case may be.

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When you went to sleep, the temperature was −2.8°C.
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D

The larger the number the warmer it is

7 0
3 years ago
PLEASE HELP WILL GIVE BRAINLIEST!!
NemiM [27]

Answer:

p<7

Step-by-step explanation:

$5 per pound

7 pounds equals $35

$5p<$35

p<35/5

p<7

7 0
3 years ago
Sample spaces For each of the following, list the sample space and tell whether you think the events are equally likely:
Schach [20]

Answer and explanation:

To find : List the sample space and tell whether you think the events are equally likely ?

Solution :

a) Toss 2 coins; record the order of heads and tails.

Let H is getting head and t is getting tail.

When two coins are tossed the sample space is {HH,HT,TH,TT}.

Total number of outcome = 4

As the outcome HT is different from TH. Each outcome is unique.

Events are equally likely since their probabilities \frac{1}{4} are same.

b) A family has 3 children; record the number of boys.

Let B denote boy and G denote girl.

If there are 3 children then the sample space is

{GGG,GGB,GBG,BGG,BBG,GBB,BGB,BBB}

The possible number of boys are 0,1,2 and 3.

Number of boys      Favorable outcome    Probability

           0                      GGG                        \frac{1}{8}

           1                    GGB,GBG,BGG          \frac{3}{8}

           2                   GBB,BGB,BBG           \frac{3}{8}

           3                       BBB                         \frac{1}{8}

Since the probabilities are not equal the events are not equally likely.

c)  Flip a coin until you get a head or 3 consecutive tails; record each flip.

Getting a head in a trial is dependent on the previous toss.

Similarly getting 3 consecutive tails also dependent on previous toss.

Hence, the probabilities cannot be equal and events cannot be equally likely.

d) Roll two dice; record the larger number

The sample space of rolling two dice is

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Now we form a table that the number of time each number occurs as maximum number then we find probability,

Highest number        Number of times         Probability

           1                                   1                     \frac{1}{36}

           2                                  3                    \frac{3}{36}

           3                                  5                    \frac{5}{36}

           4                                  7                    \frac{7}{36}

           5                                  9                    \frac{9}{36}

           6                                  11                    \frac{11}{36}

Since the probabilities are not the same the events are not equally likely.

4 0
3 years ago
Help please!! Show work if possible!
Natasha2012 [34]

Answer:

Please see the attached pictures for full solution.

5 0
3 years ago
Find the tangent of ∠I.
Nady [450]

Answer:

tanI = \frac{\sqrt{70} }{5}

Step-by-step explanation:

We require to calculate GH using Pythagoras' identity in the right triangle.

GH² + GI² = HI²

GH² + 5² = (\sqrt{95} )²

GH² + 25 = 95 ( subtract 25 from both sides )

GH² = 70 ( take square root of both sides )

GH = \sqrt{70}

Then

tanI = \frac{opposite}{adjacent} = \frac{GH}{GI} = \frac{\sqrt{70} }{5}

4 0
2 years ago
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