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kari74 [83]
3 years ago
14

HCL is slowly added to aqueous Na2CO3 forming NaCl, H2O, and CO2. Follow the steps above to write a balanced equation for this r

eaction .
Chemistry
1 answer:
user100 [1]3 years ago
4 0

 The  balanced  equation is as  below

Na2CO3 +2 HCl → 2 NaCl  +H2O  + CO2

<u><em>Explanation</em></u>

 step 1 : write  the unbalanced chemical  equation

that is  Na2CO3  +  HCl→  NaCl  + H2O  +CO2

Step 2: change  the coefficient ( <em>number in front  of chemical  formula)  </em>to make  sure  the  number of  atoms  of  an  element  are the same in both side.


By adding 2 in front  of HCl  and  in front  of NaCl  balance the    equation.

Therefore the balanced equation is as  below

Na2CO3  +2HCl  → 2NaCl  +H2O +Co2

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Answer:

\sf \boxed{4} \mapsto Pipet

\sf\boxed{7}\mapsto Test \:tube \: rack

\sf\boxed{3}\mapsto Test\: table

\sf\boxed{5}\mapsto Scoopula

\sf\boxed{1}\mapsto Graduated\: cylinder

\sf\boxed{9}\mapsto Bunsen \:burner

\sf\boxed{2}\mapsto Beaker

\sf \boxed{8}\mapsto Spot\: plate

\sf\boxed{6}\mapsto Goggles

Explanation:

Pipet is used to dispense a very small amount of liquid.

Test tube rack is used to hold multiple test tubes at the same time.

Test Table is used to view chemical reactions or hold or heat small amounts of substance.

Scoopula is used to dispense chemicals from a larger container.

Graduated cylinder is used to measure volume very precisely.

Bunsen burner is used to heat objects.

Beaker is used to transport heat or store substance.

Spot plate is used to observe the color changes of small quantities of a reacting mixture.

Goggles are used to protect the eyes from flying objects or chemical splashes.

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7 0
3 years ago
The balanced reaction between aqueous nitric acid and aqueous strontium hydroxide is ________.
Kaylis [27]
<span>d.2HNO3 (aq) + Sr(OH)2 (aq) → 2H2O (l) + Sr(NO3)2(aq)
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8O                                                  8O
2N                                                  2N
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How are sea slugs able to make their own food like green algae?
Nadusha1986 [10]

Answer: my answer I’d D! I’m sorry if this did not help you

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3 0
3 years ago
Read 2 more answers
What does Hess's law state can be done in order to be able to react solid magnesium with oxygen gas safely (that is, without exp
aleksley [76]

Answer:

C. The reaction can be broken down and performed in steps

Explanation:

Hess's Law of Constant Heat Summation states that irrespective of the number of steps followed in a reaction, the total enthalpy change for the reaction is the sum of all enthalpy changes corresponding to all the steps in the overall reaction. The implication of this law is that  the change of enthalpy in a chemical reaction is independent of the pathway between the initial and final states of the system.

To obtain MgO safely without exposing magnesium to flame, the reaction sequence shown in the image attached may be carried out. Since the enthalpy of the overall reaction is independent of the pathway between the initial and final states of the system, the sum of the enthalpy of each step yields the enthalpy of formation of MgO.

3 0
3 years ago
Rank these acids according to their expected pKa values.
givi [52]

Answer:

According to their expected pKa values, the order of those acids should be:

1- Cl2CHCOOH is the strongest acid and the lowest pKa.

2- ClCH2COOH is a strong acid, but no more than the first. Medium pKa value.

3- ClCH2CH2COOH is a strong acid, but no more than the two previous acids. High pKa value.

4- CH3CH2COOH  is the weakest acid, so the highest pKa value.

Explanation:

The pKa values are the negative logarithm of dissociation constant. It represents the relative strengths of the acids. Stronger acids show smaller pKa values and weak acids present larger pKa value. The stronger the acid, the weaker it's the conjugate base. The larger the pKa of the conjugate base, the stronger the acid. The strength of an acid is inversely related to the strength of its conjugate.

Conjugate bases are the substance that has one less proton than the parent acid. The conjugate base of the acid presented in the problem are:

ClCH2COOH -> ClCH2COO-  + H+

ClCH2CH2COOH -> ClCH2CH2COO- + H+

CH3CH2COOH -> CH3CH2COO- + H+

Cl2CHCOOH -> Cl2CHCOO - + H+

Cl2CHCOOH. The negative charge presented on its conjugate base is by resonance and inductive effect. This is the strongest acid.

ClCH2COOH. A negative charge is stabilized by resonance and electron-withdrawing but only one atom is present. So this acid is less strong than the first one.

ClCH2CH2COOH. The negative charge is stabilized by resonance and electron-withdrawing atom but the effect is less compared to the two acids showed previously.

CH3CH2COOH. The negative charge is stabilized by resonance and destabilized due to CH3 group. This is the weakest acid among the problem.

Stronger acids have smaller pKa values and weak acids have larger pKa values. Due to the information present in this problem, Cl2CHCOOH is the strongest acid and the lowest pKa. CH3CH2COOH is the weakest acid, so the highest pKa value.

Finally, we can conclude that according to their expected pKa values, the order of those acids should be:

1- Cl2CHCOOH is the strongest acid and the lowest pKa.

2- ClCH2COOH is a strong acid, but no more than the first. Medium pKa value.

3- ClCH2CH2COOH is a strong acid, but no more than the two previous acids. High pKa value.

4- CH3CH2COOH  is the weakest acid, so the highest pKa value.

3 0
3 years ago
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