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stepan [7]
3 years ago
14

Use the solubility rules from the Lab 4 introduction and your knowledge of qualitative separation schemes from the lab to answer

the following questions. The qualitative analysis experiment you did is actually an abbreviated version of a much larger analysis scheme in which many different cations are separated and identified. Suppose a mixture contains Ag , K , NH4 , Hg22 , Pb2 , Mg2 , Sr2 , Ba2 , Cu2 , Al3 and Fe3 .
(a) Which of the following ions could you separate, by causing them to precipitate, with the addition of HCl?
Ag+ K+ NH4+
Hg22+ Pb2+ Mg2+
Sr2+ Ba2+ Cu2+
Al3+ Fe3+
(b) After the addition of HCl, the above sample is centrifuged and decanted. Which of the following cations remaining in the supernatant could you separate, by causing them to precipitate, with the addition of H2SO4? (Hint: H2SO4 is a source of sulfate ions. Select all that apply.)
Ag+ K+ NH4+
Hg22+ Pb2+ Mg2+
Sr2+ Ba2+ Cu2+
Al3+ Fe3+
Chemistry
1 answer:
cluponka [151]3 years ago
4 0

Answer:

a13+a13

Explanation:

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Remember, 1 mole= 6.022x10^23 atoms, molecules, or formula units.

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3 years ago
Potassium chloride dissolved in pure water is an
postnew [5]

Answer:

A) An ionic compound dissolved in a polar solvent

Explanation:

Potassium Chloride's chemical formula is KCl. Most ionic compounds are formed between a nonmetal and a metal. In this case, potassium is acting as the metal and chloride is the nonmetal. Water is a polar solvent due to the electronegativity of the oxygen in the molecule creating a partial negative pole, leaving the hydrogen atoms partially positive. Hence, A is your best answer.

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8 0
3 years ago
Read 2 more answers
an engineer wishes to design a container that will hold 12.0 mol of ethane at a pressure no greater than 5.00x10*2 kPa and a tem
OleMash [197]

Answer:

The minimum volume of the container is 0.0649 cubic meters, which is the same as 64.9 liters.

Explanation:

Assume that ethane behaves as an ideal gas under these conditions.

By the ideal gas law,

P\cdot V = n\cdot R\cdot T,

\displaystyle V = \frac{n\cdot R\cdot T}{P}.

where

  • P is the pressure of the gas,
  • V is the volume of the gas,
  • n is the number of moles of particles in this gas,
  • R is the ideal gas constant, and
  • T is the absolute temperature of the gas (in degrees Kelvins.)

The numerical value of R will be 8.314 if P, V, and T are in SI units. Convert these values to SI units:

  • P =\rm 5.00\times 10^{2}\;kPa = 5.00\times 10^{2}\times 10^{3}\; Pa = 5.00\times 10^{5}\; Pa;
  • V shall be in cubic meters, \rm m^{3};
  • T = \rm 52.0 \textdegree C = (52.0 + 273.15)\; K = 325.15\; K.

Apply the ideal gas law:

\displaystyle \begin{aligned}V &= \frac{n\cdot R\cdot T}{P}\\ &= \frac{12.0\times 8.314\times 325.15}{5.00\times 10^{5}}\\ &= \rm 0.0649\; m^{3} \\ &= \rm (0.0649\times 10^{3})\; L \\ &=\rm 64.9\; L\end{aligned}.

4 0
3 years ago
How much heat must your body transfer to 500.0g of water to heat it from 25.0°C to body temperature, 37.0°C?
shtirl [24]

Answer : The heat your body transfer must be, 25.1 kJ

Explanation :

Formula used :

Q=m\times c\times \Delta T

or,

Q=m\times c\times (T_2-T_1)

where,

Q = heat = ?

m = mass of water = 500.0 g

c = specific heat of water = 4.18J/g^oC

T_1 = initial temperature  = 25.0^oC

T_2 = final temperature  = 37.0^oC

Now put all the given value in the above formula, we get:

Q=500.0g\times 4.18J/g^oC\times (37.0-25.0)K

Q=25080J=25.1kJ

Therefore, the heat your body transfer must be, 25.1 kJ

3 0
3 years ago
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