The volume of titanium with mass of 0. 10g and density of 4. 51 g/cm³ is 0. 02 cm³
<h3>
What is volume?</h3>
Volume is known to be equal to the mass divided by the density.
It is written thus:
Volume = Mass / density
<h3>
How to calculate the volume</h3>
The volume is calculated using the formula:
Volume = mass ÷ density
Given the mass = 0. 10g
Density = 4.51 g/cm³
Substitute the values into the formula
Volume of titanium = 0. 10 ÷ 4.51 = 0. 02 cm³
Thus, the volume of titanium with mass of 0. 10g and density of 4. 51 g/cm³ is 0. 02 cm³
Learn more about volume here:
brainly.com/question/1762479
#SPJ1
The arrangement of particles that make up an ionic compound would be an ionic lattice type of crystal arrangement. An ionic lattice type of structure will be formed due to many of the ionic bonds formed between the oppositely charged ions of the metal and nonmetal.
Answer:
The elements are in the same column/group IIA.
See the explanation below, please.
Explanation:
The elements Calcium, Strontium, Beryllium, Magnesium, Barium and Radio, belong to the group of alkaline earth metals located in group IIA of the periodic table, they require 2 electrons to complete their octet (they have 2 valence electrons). reagents than alkali metals.
Explanation:
The given data is as follows.
= 250 mL, 
= 750 mL
= 
= 35 + 273 K = 308 K
= 35 + 273 K = 308 K
= 0.55 atm, 
= 1.5 atm
P = ? , V = 10.0 L
Since, temperature is constant.
So, 
= PV
Now, putting the given values into the above formula as follows.
= PV
= 
P = 0.126 atm
As, 1 atm = 760 torr. So, 
= 95.76 torr.
Thus, we can conclude that the final pressure, in torr, of the mixture is 95.76 torr.
11.48-gram of 
are needed to produce 6.75 Liters of 
gas measured at 1.3 atm pressure and 298 K
<h3>What is an ideal gas equation?</h3>
The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
First, calculate the moles of the gas using the gas law,
PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.
Given data:
P= 1.3 atm
V= 6.75 Liters
n=?
R= 
T=298 K
Putting value in the given equation:
Moles = 0.3588 moles
Now,
Mass= 11.48 gram
Hence, 11.48-gram of are needed to produce 6.75 Liters of gas measured at 1.3 atm pressure and 298 K
Learn more about the ideal gas here:
brainly.com/question/27691721
#SPJ1
