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dalvyx [7]
3 years ago
15

A 0.320 g sample of a carboxylic acid is burned in oxygen, producing 0.571 g of co2 and 0.235 g of h2o. Determine the empirical

formula of the carboxylic acid.
Chemistry
1 answer:
Anestetic [448]3 years ago
6 0

Answer:- Empirical formula of the carboxylic acid is C_3H_6O_2 .

Solution:- When the acid is burned then all it's carbon goes to form carbon dioxide and all the hydrogen goes to form water.

So, we convert the grams of carbon dioxide to moles and calculate the moles of carbon from it as one mol of carbon dioxide contains one mol of carbon.

0.571gCO_2(\frac{1molCO_2}{44gCO_2})(\frac{1molC}{1molCO_2})

= 0.0130molC

Similarly, we convert the grams of water to moles and these moles are used to calculate the moles of hydrogen as each mol of water contains two moles of hydrogen.

0.235gH_2O(\frac{1molH_2O}{18gH_2O})(\frac{2molH}{1molH_2O})

= 0.0261molH

Now, we convert the moles of C and H to grams and subtract the sum of their mass from the given mass of the acid to calculate the mass of oxygen present in the acid.

0.0130molC(\frac{12gC}{1molC})

= 0.156 g C

Similarly,  0.0261molH(\frac{1gH}{1molH})

= 0.0261 g H

mass of oxygen in acid = 0.320 g - (0.156 g + 0.0261 g)

= 0.320 g - 0.1821 g

= 0.1379 g

Let's convert the grams of oxygen to moles;

0.1379gO(\frac{1molO}{16gO})

= 0.00862 mol O

Next step is to calculate the mol ratio and for this we divide the moles ofch by the least one of them. We have least moles of oxygen, so let's divide the moles of each by the moles of oxygen.

C=\frac{0.0130}{0.00862}=1.5

H=\frac{0.0261}{0.00862}=3.0

O=\frac{0.00862}{0.00862}=1.0

Mol ratio sgould be whole number ratio, if it is not then we multiply all of them by 2, 3, 4 and so on to get the smallest whole number ratio. Here if we multiply by 2 then it works.

So, C = 2(1.5) = 3

H = 2(3.0) = 6

O = 2(1.0) = 2

Hence, the empirical formula of the carboxylic acid is C_3H_6O_2 .

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Two identical 732.0 L tanks each contain 212.0 g of gas at 293 K, with neon in one tank and nitrogen in the other. Based on the
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A balloon is filled with 35.0 L of helium in the morning when the temperature is 303 degrees kelvin. By 3:00 p.m., the temperatu
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Answer:

The new volume of the balloon is 38.5 L

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Volume by 3pm = TO BE DETERMINED

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<u>Step 2: </u>Calculate the new volume

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7 0
3 years ago
Read 2 more answers
A drop of water with a mass of 0.48 g is vaporized at 100 ∘C and condenses on the surface of a 55- g block of aluminum that is i
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The final temperature in Celsius of the metal block is 49°C.

<h3>How to find the number of moles ?</h3>

Moles water = \frac{\text{Given mass}}{\text{Molar Mass}}

                     = \frac{0.48\ g}{18\ \text{g/mol}}

                     = 0.0266 moles  

                   

Heat lost by water = 0.0266 mol x 44.0 kJ/mol

                                = 1.17 kJ

                                = 1170 J           [1 kJ = 1000 J]

Heat lost = Heat gained

Heat gained by aluminum = 1170 J  

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1170 + 1242 = 49.7 T  

T = 48.5°C (49°C at two significant figures)

Thus from the above conclusion we can say that The final temperature in Celsius of the metal block is 49°C.

Learn more about the Moles here: brainly.com/question/15356425

#SPJ1

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