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3 years ago

If A= (-1,-3) and B = (11,-8), what is the length of Ad?

Mathematics

1 answer:

Fynjy0 [20]3 years ago

7 0

Answer:

Step-by-step explanation:

The formula of a distance between two points

$A(x_1,\ y_1),\ B(x_2,\ y_2)\\\\d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

We have the points A(-1, -3) and B(11, -8).

Substitute:

$AB=\sqrt{(-8-(-3))^2+(11-(-1))^2}=\sqrt{(-8+3)^2+(11+1)^2}\\\\=\sqrt{(-5)^2+12^2}=\sqrt{25+144}=\sqrt{169}=13\\\\\sqrt{169}=13\ \text{because}\ 13^2=169$

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Answer:

$36x^6y^3$

Step-by-step explanation:

The problem needs application of law of indices

$1. (xy)^m = x^my^m$

This means common power for terms can be applied to each term individually.

$x^a x^b = x^(a+b)\\$

Separate power for the terms having same base can be added together.

_______________________________________________________

we will be using these law of indices in the problem

$(3xy)^2x^4y \\=> 3^2x^2y^2x^4y$

applied the first rule of indices as mentioned above

$3^2x^2y^2x^4y\\=>9*x^(2+4)4y^(2+1)\\=>9*4x^6y^3\\=>36x^6y^3$

applied the second rule of indices as mentioned above

Thus, simplified form of (3xy)^2x^4y is $36x^6y^3$ .

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4 years ago

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4 years ago

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3 years ago

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Kisachek [45]

Answer:

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